NCERT Solutions of class 10 science chapter 4-Carbon and its Compounds
Class 10 NCERT science solutions of chapter 4-Carbon and its Compound are created by an expert teacher of Future Study Point which is one of the growing educational websites of India. All NCERT science solutions of chapter 4 are explained through step by step method in such a way that students can understand easily, however, if you face any problem, don’t hesitate to ask us in the comment box, we will reply inst7bhantly.
Chapter 4 of class 10 science -Carbon and its compound is most important chapter because the maximum number of questions are always asked in the class 10 science paper during CBSE board exams.
In this chapter Carbon and its Compound, you will study , the types of carbon compounds, their nomenclatures, IUPAC name, catenation property of carbon atoms, addition property of carbonic compounds, properties of carboxylic acid, and alcohol, saponification, esterification, etc.
NCERT Solutions of Class 10 Science
NCERT Solutions of class 10 science chapter 4-Carbon and its Compounds
Page no 61
Q1.What would be the electron dot structure of carbon dioxide which has the formula CO2?
Ans.The electron dot structure of CO2 is
Q2.What would be the electron dot structure of a molecule of sulphur which is made up of eight atoms of sulphur? (Hint − the eight atoms of sulphur are joined together in the form of a ring.)
Ans.Electron dot structure of a sulphur molecule
Page No 1
Q1.How many structural isomers can you draw for pentane?
Ans. Three structural isomers are possible for pentane.
(i) n-pantane (ii) Isopantane (iii) Neopantane
Q2.What are the two properties of carbon which lead to the huge number of carbon compounds we see around us?
Ans.The two features of carbon that give rise to a large number of compounds are as follows:
(i) Catenation − It is the ability to form bonds with other atoms of carbon.
(ii) Tetravalency − With the valency of four, carbon is capable of bonding with four other atoms.
Q3.What will be the formula and electron dot structure of cyclopentane?
Ans. The formula for cyclopentane is C5H10. Its electron dot structure is given below.
Page no 69
Q4.Draw the structures for the following compounds.
(i) Ethanoic acid (ii) Bromopentane.
(iii) Butanone (iv) Hexanal
Are structural isomers possible for Bromo pentane?
(ii) There are many structural isomers possible for Bromo pentane. Among them, the structures of three isomers are given.
(i) 1-Bromopantane (ii) 2-Bromopantane (iii) 3-Bromopantane
Page no 68
Q1.How would you name the following compounds?
(ii) Methanal (formaldehyde)
Q2.Why do ionic compounds have high melting points?
Ans.Ionic compounds have strong electrostatic forces of attraction between the ions. Therefore, it requires a lot of energy to overcome these forces. That is why ionic compounds have high melting points.
Page no 71
Q1.Why is the conversion of ethanol to ethanoic acid an oxidation reaction?
CH3CH2OH + (Alkaline KMnO4) → CH3COOH
Since the conversion of ethanol to ethanoic acid involves the addition of oxygen to ethanol, it is an oxidation reaction.
Q2.A mixture of oxygen and ethyne is burnt for welding. Can you tell why a mixture of ethyne and air is not used?
Ans.When ethyne is burnt in air, it gives a sooty flame. This is due to incomplete combustion caused by limited supply of air. However, if ethyne is burnt with oxygen, it gives a clean flame with temperature 3000°C because of complete combustion. This oxy-acetylene flame is used for welding. It is not possible to attain such a high temperature without mixing oxygen. This is the reason why a mixture of ethyne and air is not used.
2HC ≡ CH + 5O2 → 4CO2 + 2H2O + Heat
Q1.How would you distinguish experimentally between alcohol and carboxylic acid?
Ans.We can distinguish between an alcohol and a carboxylic acid on the basis of their reaction with carbonates and hydrogen carbonates. Acid reacts with carbonate and
hydrogen carbonate to evolve CO2 gas that turns lime water milky.
Ex. CH₃COOH(aq) + NaHCO₃(s) = CH₃COONa(s) + H₂CO₃(aq)
CH3COOH(aq) + Na2CO3(s) = CH3COONa(s) + H20(l) + CO2(g)
Alcohols, on the other hand, do not react with carbonates and hydrogen carbonates.
Q2.What are oxidising agents?
Ans.Some substances such as alkaline potassium permanganate and acidified potassium dichromate are capable of adding oxygen to others. These are known as oxidizing agents.
Q1.Would you be able to check if water is hard by using a detergent?
Ans.Detergents are ammonium or sulphonate salts of long chain carboxylic acids. Unlike soap, they do not react with calcium and magnesium ions present in hard water to form scum. They give a good amount of lather irrespective of whether the water is hard or soft. This means that detergents can be used in both soft and hard water. Therefore, it cannot be used to check whether the water is hard or not.
Q2.People use a variety of methods to wash clothes. Usually after adding the soap, they ‘beat’ the clothes on a stone, or beat it with a paddle, scrub with a brush or the mixture is agitated in a washing machine. Why is agitation necessary to get clean clothes?
Ans.A soap molecule has two parts namely hydrophobic and hydrophilic. With the help of these, it attaches to the grease or dirt particle and forms a cluster called micelle. These micelles remain suspended as a colloid. To remove these micelles (entrapping the dirt), it is necessary to agitate clothes.
Q1.Ethane, with the molecular formula C2H6 has
(a) 6 covalent bonds.
(b) 7 covalent bonds.
(c) 8 covalent bonds.
(d) 9 covalent bonds.
Ans.(b) Ethane has 7 covalent bonds.
Q2.Butanone is a four-carbon compound with the functional group
(a) carboxylic acid.
Ans.(c) The functional group of butanone is ketone.
Q3.While cooking, if the bottom of the vessel is getting blackened on the outside, it means that
(a) the food is not cooked completely.
(b) the fuel is not burning completely.
(c) the fuel is wet.
(d) the fuel is burning completely.
Ans.(b) While cooking, if the bottom of the vessel is getting blackened on the outside, then it means that the fuel is not burning completely.
Q4.Explain the nature of the covalent bond using the bond formation in CH3Cl.
Ans. The structure of CH3Cl is given below.
Carbon can neither lose four of its electrons nor gain four electrons as both the processes require extra amount of energy and would make the system unstable. Therefore, it completes its octet by sharing its four electrons with other carbon atoms or with atoms of other elements. The bonds that are formed by sharing electrons are known as covalent bonds. In covalent bonding, both the atoms share the valence electrons, i.e., the shared electrons belong to the valence shells of both the atoms.
Here, carbon requires 4 electrons to complete its octet, while each hydrogen atom requires one electron to complete its duplet. Also, chlorine requires an electron to complete the octet. Therefore, all of these share the electrons and as a result, carbon forms 3 bonds with hydrogen and one with chlorine.
Q5.Draw the electron dot structures for
(a) ethanoic acid.
Q6.What is a homologous series? Explain with an example.
Ans.A homologous series is a series of carbon compounds that have different numbers of carbon atoms but contain the same functional group. For example, methane, ethane, propane, butane, etc. are all part of the alkane homologous series. The general formula of this series is CnH2n+2.
It can be noticed that there is a difference of −CH2 unit between each successive compound.
Q7.How can ethanol and ethanoic acid be differentiated on the basis of their physical and chemical properties?
Ans.Ethanol is a liquid at room temperature with a pleasant odour while ethanoic acid has vinegar-like smell. The melting point of ethanoic acid is 17°C. This is below room
temperature and hence, it freezes during winters.
Ethanoic acid reacts with metal carbonates and metal hydrogencarbonates to form salt, water, and carbon dioxide gas while ethanol does not react with them.
Q8.In the electrolytic refining of a metal M, what would you take as the anode, the cathode and the electrolyte?
Ans.In the electrolytic refining of a metal M:
Anode → Impure metal M
Cathode → Thin strip of pure metal M
Electrolyte → Solution of salt of the metal M
Q9.Why are carbon and its compounds used as fuels for most applications?
Ans.Most of the carbon compounds give a lot of heat and light when burnt in air. Saturated hydrocarbons burn with a clean flame and no smoke is produced. The carbon compounds, used as a fuel, have high calorific values. Therefore, carbon and its compounds are used as fuels for most applications.
Q10.Explain the formation of scum when hard water is treated with soap.
Ans.Soap does not work properly when the water is hard. A soap is a sodium or potassium salt of long chain fatty acids. Hard water contains salts of calcium and magnesium. When soap is added to hard water, calcium and magnesium ions present in water displace sodium or potassium ions from the soap molecules forming an insoluble substance called scum. A lot of soap is wasted in the process.
Q11.What change will you observe if you test soap with litmus paper (red and blue)?
Ans.Since soap is basic in nature, it will turn red litmus blue. However, the colour of blue litmus will remain blue.
Q12.What is hydrogenation? What is its industrial application?
Ans.Hydrogenation is the process of addition of hydrogen. Unsaturated hydrocarbons are added with hydrogen in the presence of palladium and nickel catalysts to give saturated hydrocarbons.
This reaction is applied in the hydrogenation of vegetables oils, which contain long chains of unsaturated carbons.
Q13.Which of the following hydrocarbons undergo addition reactions: C2H6, C3H8, C3H6, C2H2 and CH4.
Ans. Unsaturated hydrocarbons undergo addition reactions. Being unsaturated hydrocarbons, C3H6 and C2H2 undergo addition reactions.
Q14.Give a test that can be used to differentiate chemically between butter and cooking oil.
Ans. Butter contains saturated fats. Therefore, it cannot be hydrogenated. On the other hand, oil has unsaturated fats. That is why it can be hydrogenated to saturated fats (solids).
Q15.Explain the mechanism of the cleaning action of soaps.
Ans.The cleansing action of soaps: The dirt present on clothes is organic in nature and insoluble in water. Therefore, it cannot be removed by only washing with water. When soap is dissolved in water, its hydrophobic ends attach themselves to the dirt and remove it from the cloth. Then, the molecules of soap arrange themselves in micelle formation and trap the dirt at the centre of the cluster. These micelles remain suspended in the water. Hence, the dust particles are easily rinsed away by water.
NCERT Solutions of Science and Maths for Class 9,10,11 and 12
NCERT Solutions of class 9 maths
|Chapter 1- Number System||Chapter 9-Areas of parallelogram and triangles|
|Chapter 2-Polynomial||Chapter 10-Circles|
|Chapter 3- Coordinate Geometry||Chapter 11-Construction|
|Chapter 4- Linear equations in two variables||Chapter 12-Heron’s Formula|
|Chapter 5- Introduction to Euclid’s Geometry||Chapter 13-Surface Areas and Volumes|
|Chapter 6-Lines and Angles||Chapter 14-Statistics|
|Chapter 7-Triangles||Chapter 15-Probability|
|Chapter 8- Quadrilateral|
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NCERT solutions of class 11 maths
|Chapter 1-Sets||Chapter 9-Sequences and Series|
|Chapter 2- Relations and functions||Chapter 10- Straight Lines|
|Chapter 3- Trigonometry||Chapter 11-Conic Sections|
|Chapter 4-Principle of mathematical induction||Chapter 12-Introduction to three Dimensional Geometry|
|Chapter 5-Complex numbers||Chapter 13- Limits and Derivatives|
|Chapter 6- Linear Inequalities||Chapter 14-Mathematical Reasoning|
|Chapter 7- Permutations and Combinations||Chapter 15- Statistics|
|Chapter 8- Binomial Theorem||Chapter 16- Probability|
NCERT solutions of class 12 maths
|Chapter 1-Relations and Functions||Chapter 9-Differential Equations|
|Chapter 2-Inverse Trigonometric Functions||Chapter 10-Vector Algebra|
|Chapter 3-Matrices||Chapter 11 – Three Dimensional Geometry|
|Chapter 4-Determinants||Chapter 12-Linear Programming|
|Chapter 5- Continuity and Differentiability||Chapter 13-Probability|
|Chapter 6- Application of Derivation||CBSE Class 12- Question paper of maths 2021 with solutions|
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