Author name: Narender Kumar

I am Narender Kumar, an educator and the creator of Future Study Point. I hold an M.Sc. in Physics from HNB University. I create easy-to-understand Mathematics and Science lessons, NCERT solutions, important questions, MCQs, sample papers and video explanations for CBSE and NCERT students from Classes 6 to 12. My aim is to help students build strong concepts, practise effectively and prepare confidently for their examinations.

Gravitational Potential vs Electric Potential: Understanding Potential Difference in an Electric Field
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Gravitational Potential vs Electric Potential: Understanding Potential Difference in an Electric Field

To understand Understanding Potential Difference in an Electric Field, we should first develop a clear idea of potential energy. A simple gravitational example helps us build this connection. Just as an object possesses gravitational potential energy because of its position in a gravitational field, a charged particle can possess electric potential energy because of its position in an electric field. This analogy provides a strong foundation for understanding electric potential, potential difference, voltage, and electric potential energy. Once these ideas are connected logically, many concepts in electricity become much easier to understand. The aim is not merely to memorize formulas, but to develop a physical understanding that helps science students clear their doubts and confidently move towards more advanced concepts of electricity and electric fields. Gravitational Potential Energy: A Simple Analogy Suppose an object of mass mm is lifted from point A on the ground to point B, at a height hh. The gravitational force acting on the object is F=mg where: If the object is lifted through a vertical distance hh, the work done against gravity is W=F×d Therefore,W=mg×hW=mg\times h orW=mghW=mgh This work does not simply disappear. It is stored as gravitational potential energy of the object. Therefore, at height hh, U=mgh​ where UU represents gravitational potential energy. For convenience, we can choose the ground as the reference level and take the gravitational potential energy there to be zero. Thus, UA​=0 and at point BB,UB=mghU_B=mgh But what is gravitational potential? Here we need to make an important distinction. Potential energy depends on the mass of the object: U=mgh whereas gravitational potential is potential energy per unit mass:ϕ=Um=gh\phi=\frac{U}{m}=gh So, gravitational potential tells us about the potential energy available per unit mass at a particular point in a gravitational field. This idea helps us understand electric potential. What Is Electric Potential? An electric field is a region of space in which an electric charge experiences an electric force. To define the electric potential at a point, we consider a small positive test charge and calculate the work required to bring it from a reference point to that location. Usually, for an isolated charge system, infinity is taken as the reference point and the electric potential at infinity is taken to be zero. Therefore, the electric potential at a point is defined as: The work done by an external agent in bringing a unit positive test charge from infinity to that point, without changing its kinetic energy. Mathematically, V=W​​/Q where: The SI unit of electric potential is the volt (V). One volt is defined as: 1 V=1 J/C​ This means that if 1 joule of work is required to bring a 1 coulomb positive charge to a point, the electric potential of that point is 1 volt relative to the chosen reference. Electric Potential and Electric Potential Energy Are Different This distinction is very important. Electric potential VV is potential energy per unit charge: V=U​​/Q Therefore, U=V​Q Here: This is analogous to gravitational potential: Gravitational potential = Gravitational potential energy Mass Similarly, Electric potential = Electric potential energy Charge So, just as gravitational potential tells us about energy per unit mass, electric potential tells us about energy per unit charge. What Is Potential Difference? Now consider two points, A and B, in an electric field. Suppose their electric potentials are VAV_A and VBV_B. The potential difference between A and B is the difference between their electric potentials: VAV_A – VBV_B If a charge Q moves from A to B, the change in its electric potential energy is related to the potential difference. For a positive charge, the work done by the electric field in moving the charge from A to B is W=Q( VAV_A – VBV_B )​ Therefore, VAV_A – VBV_B ​=W​​/Q where WW here represents the work done by the electric field. There is an important point here: if we instead talk about the work done by an external agent in moving the charge slowly from A to B, the sign is reversed: Wexternal​=Q(VB​−VA​) This distinction prevents confusion about the sign of work. Why Does Potential Difference Produce Electric Current? A potential difference does not automatically mean that current will flow. For current to flow continuously, there must generally be a closed conducting path and mobile charge carriers. When a potential difference is applied across a conductor, an electric field is established inside the conductor. This electric field exerts force on the mobile charge carriers and causes their net drift motion. This organized movement of charge is called electric current. Therefore, we can say: Potential difference provides the energy per unit charge that drives charge through a circuit. When a conducting path is available, this can produce an electric current. For example, a battery maintains a potential difference between its terminals. When the terminals are connected through a conducting circuit, charges move through the circuit and current flows. Potential Difference Across a Conductor Suppose a conductor is connected between points A and B. If the potential at A is VAV_A and the potential at B is VBV_B, then the potential difference is V=VAV_A​−VBV_B if we define the voltage from A to B in that direction. If a charge QQ moves through a potential difference VV, the corresponding energy transferred is W=QV​ Therefore, V= W/Q This equation gives the physical meaning of voltage: Voltage tells us how much energy is transferred per unit charge. For example, a potential difference of 12 V means that 12 joules of energy are transferred per coulomb of charge. 12 V=12 J/C How Is a Potential Difference Generated Between Clouds and the Earth? One of the most spectacular examples of a very large potential difference in nature is lightning. Inside a thundercloud, powerful upward and downward air currents cause collisions among ice crystals, supercooled water droplets, and larger ice particles such as graupel. These collisions can cause charge separation within the cloud. As a result, different regions of the cloud acquire different net charges. Typically, the lower part of a thundercloud becomes predominantly negatively charged, while the upper region becomes

Class 10 Maths NCERT Solutions for Chapter 12 Surface Areas & Volumes
Class 10 Maths, Class 10 Maths NCERT Solutions

Class 10 Maths NCERT Solutions for Chapter 12 Surface Areas & Volumes

Class 10 Maths Chapter 12 Surface Areas & Volumes NCERT Solutions are extremely important for understanding the concepts of Surface Areas and Volumes. This chapter involves different types of solids such as combinations of solids, cylinders, cones, spheres and hemispheres. By practising the NCERT questions step by step, students can understand how to identify the required formula, substitute the given values correctly and solve questions systematically. For CBSE Board Exam preparation, Class 10 Maths NCERT Solutions play a very important role. Students should thoroughly practise the NCERT textbook questions because they help in developing a strong understanding of mathematical concepts and the correct method of solving problems. Regular practice of these solutions can also help students improve their accuracy, calculation skills and confidence before the board examination. Students preparing for the CBSE Class 10 Maths Board Exam should revise Chapter 12 Surface Areas and Volumes multiple times and maintain a proper revision cycle. Along with understanding the formulas, focus on the logic behind each question and practise writing complete step-by-step solutions. These Class 10 Maths Chapter 12 NCERT Solutions can be useful for school exams, pre-board exams, half-yearly exams and final CBSE Board Exam preparation. Class 10 Maths Chapter 12 NCERT Solutions as per CBSE 2026–27 Exercise –12.1 These Class 10 Maths Chapter 12 NCERT Solutions are prepared according to the CBSE 2026–27 syllabus and curriculum. The chapter Surface Areas and Volumes includes Exercise 12.1 and Exercise 12.2, and all the questions from these exercises have been solved here step by step by a CBSE-experienced Maths teacher to help students understand the concepts clearly and prepare effectively for their examinations. Exercise 12.1 focuses on calculating the surface areas of composite solids formed by combining two or more basic three-dimensional figures. In this exercise, you will solve problems involving common 3D shapes such as cubes, cuboids, cylinders, cones, and spheres or hemispheres joined together. The key is to identify the exposed surface areas of each component shape—such as adding the curved surface areas of adjacent parts while subtracting any overlapping bases—to determine the total outer surface area of the combined figure. Video Solutions of Exercise 12.1 Class 10 Maths Chapter 12 NCERT Solutions as per CBSE 2026–27 Exercise –12.2 Exercise 12.2 shifts the focus to calculating the total volume of combined three-dimensional geometrical figures. Similar to the previous section, the questions involve 3D shapes like cylinders, cones, spheres, hemispheres, and cuboids combined or hollowed out from one another. Unlike surface area, volume calculations are strictly additive or subtractive, requiring you to sum the volumes of individual solid components or subtract the volume of any removed cavities to find the total capacity or space occupied by the composite structure. Would you like to review any specific formulas or step-by-step solutions for questions in these exercises? video Solutions of Exercise 12.2 Class 10 Maths NCERT Solutions for Chapter 12 – Surface Areas & Volumes NCERT Solutions Class 10 Maths NCERT Solutions for Chapter 12 – Surface Areas & Volumes Exercise 12.1 Q1.2 cubes each of volume 64 cm³ are joined end to end. Find the surface area of the resulting cuboid. Solution Two 4 cm cubes joined end to end form an 8 × 4 × 4 cuboid Volume of each cube = Side³ = 64, so Side = ∛64 = 4 cm. Dimensions of resulting cuboid Length l = 4 + 4 = 8 cm, Breadth b = 4 cm, Height h = 4 cm Surface area Surface area = 2(lb + bh + hl) = 2(8×4 + 4×4 + 4×8) = 2(32 + 16 + 32) = 2 × 80 = 160 Hence the required surface area of the resulting cuboid = 160 cm² Q2.A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area of the vessel. Solution Hollow hemisphere (radius 7 cm) mounted by a hollow cylinder (height 6 cm) Height of vessel = 13 cm. Diameter of hemisphere = 14 cm, so radius r = 7 cm. Height of cylinder = 13 − 7 = 6 cm Inner surface area = CSA of hemisphere + CSA of cylinder CSA of hemisphere = 2πr² = 2 × 22/7 × 7² = 308 cm² CSA of cylinder = 2πrh = 2 × 22/7 × 7 × 6 = 264 cm² Inner surface area of vessel = 308 + 264 = 572 cm² Q3.A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of the same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy. Solution Cone mounted on a hemisphere, both of radius 3.5 cm Height of cone = 15.5 − 3.5 = 12 cm. Radius of hemisphere = cone = 3.5 cm. Total surface area = CSA of hemisphere + CSA of cone CSA of hemisphere = 2πr² = 2 × 22/7 × 3.5 × 3.5 = 77 cm² Slant height l = √(r² + h²) = √(3.5² + 12²) = √156.25 = 12.5 cm CSA of cone = πrl = 22/7 × 3.5 × 12.5 = 137.5 cm² Total surface area = 77 + 137.5 = 214.5 cm² Q4.A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have? Find the surface area of the solid. Solution Hemisphere of diameter 7 cm surmounted on a 7 cm cube The greatest diameter of the hemisphere equals the side of the cube = 7 cm, so radius r = 3.5 cm. Surface area = TSA of cube + CSA of hemisphere − area of hemisphere base TSA of cube = 6 × side² = 6 × 7 × 7 = 294 cm² CSA of hemisphere = 2πr² = 2 × 22/7 × 3.5 × 3.5 = 77 cm² Area of base = πr² = 22/7 ×

Class 10 Half Yearly CBSE Science Question Paper Solutions
CBSE Maths Previous Years Question Papers, Class 10 Maths

Class 10 Half Yearly CBSE Science Question Paper Solutions

The Class 10 Half Yearly CBSE Board Exam 2022-23 Science Question Paper Solutions are useful for students preparing for their Class 10 Science examinations. By solving this question paper and checking the complete solutions, students can understand the types of questions asked in the CBSE examination and improve their answer-writing skills. Regular practice of previous question papers is also helpful for Class 10 CBSE Exam preparation, especially for the Half Yearly, Pre-Board and Final Board Examinations. Important for Class 10 CBSE Exam Preparation Practising the Class 10 Science Half Yearly Question Paper with Solutions can help students revise important concepts, identify their weak areas and improve their speed and accuracy. Although this question paper is from the 2022-23 academic session, its questions and concepts can be valuable for revision and examination practice. Students preparing for the Class 10 CBSE Half Yearly Exam, Pre-Board Exam and Final Board Exam should practise different question papers to become familiar with the examination pattern and important Science topics. Class 10 Science Question Paper Solutions The complete Class 10 Half Yearly CBSE Science Question Paper Solutions have been prepared with a focus on the CBSE examination pattern and answer-writing norms. Each question has been solved step-by-step in a clear and easy-to-understand manner by a qualified Science teacher, keeping in mind the concepts and presentation expected in the Class 10 CBSE examination. Students can use these solutions to check their answers, understand the correct method of solving each question, improve their answer-writing skills and identify their mistakes. The solutions are particularly useful for Class 10 CBSE Half Yearly Exam, Pre-Board Exam and Final Board Exam preparation. Students are advised to first attempt the complete question paper independently and then refer to the solutions for self-evaluation and revision. Class 10 Science Question Paper CBSE Half Yearly Exam 2022-23 With Solutions Class 10 Science Question Paper CBSE Half Yearly Exam 2022-23 With Solutions Section A MCQ’s Q1. The main cause of variation among organisms during sexual reproduction is: (a) Errors in copying DNA (b) Errors in RNA (c) Errors in both RNA and DNA (d) Genetic drift Solution: (a) Errors in copying DNA Q2. The radius of curvature of a converging mirror is 30 cm. At what distance from the mirror should an object be placed so as to obtain a virtual image? (a) Infinity (b) 30 cm (c) Between 15 cm and 30 cm (d) Between 0 cm and 15 cm Solution: (d) Between 0 cm and 15 cm The virual image formed by a concave mirror(converging mirror) when the object is located between focal point and the pole of the mirror. Therefore the distance of the object should be less than its focal length (f=30/2=15 cm) Q3. The following reaction is used for preparation of oxygen gas in laboratory: (a) It is decomposition and endothermic (b) It is combination reaction (c) It is decomposition reaction and heat is released (d) It photochemical decomposition and exothermic in nature. Solution: (a) It is decomposition and endothermic Q4. Which of the following is correct sequence of events of sexual reproduction in a flower? (a) Pollination, fertilisation, seeding, embryo (b) Seeding, embryo, fertilisation, pollination (c) Pollination, fertilisation, embryo, seeding (d) Embryo, seeding, pollination, fertilisation Solution: (c) Pollination, fertilisation, embryo, seeding Q5. What happens when dilute hydrochloric acid is added to iron fillings? (a) Hydrogen gas and iron chloride are formed (b) Chlorine gas and iron hydroxide are formed (c) No reaction takes place (d) Iron salt and water are produced Solution: (a) Hydrogen gas and iron chloride are formed Q6. Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then in parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combination would be (a) 1:2 (b) 2:1 (c) 1:4 (d) 4:1 Solution: (c) 1:4 Heat produced in the circult = V²t/R Let resistance of a wire is R Net resistance of two wires when connected in series =R+R =2R Net resistance of two wires when connected in parallel =R/2 The ratio of heat produced in series and parallel combination = V²t/2R : V²t/R/2 =1 :4 Q7. What happens when a solution of an acid is mixed with a solution of a base in a test tube? (i) temperature increases (ii) temperature decreases (iii) temperature remains same (iv) salt formation takes place (a) (i) only (b) (i) and (iii) (c) (ii) and (iii) (d) (i) and (iv) Solution: (d) (i) and (iv) Q8. The refractive index of medium A is 1.5 and that of medium B is 1.33. If the speed of light in air is 3×108 m/s, what is the speed of light in mediums A and B? (a) 2×108 m/s, 1.33×108 m/s (b) 1.33×108 m/s, 2×108 m/s (c) 2.25×108 m/s, 2×108 m/s (d) 2×108 m/s, 2.25×108 m/s Solution: Let the speed of the light in medium A is VA and in medium B is VB Refractive index of a given medium= Velocity of the light in air/Velocity of the light in the given midium In case of first medium 1.5 = 3×108 /VA VA= 3×108m/s In case of second medium 1.33= 3×108 /VB VB= 2.25×108m/s Q9. In the given food chain, suppose the amount of energy of fourth trophic level is 5 KJ, what will be the energy available at the producer level? Grass → Grasshopper → Frog → Snake → Hawk (a) 5 KJ (B) 50 KJ (C) 500 KJ (D) 5000 KJ Solution: (D) 5000 KJ Let the energy available at the producer level is = x The energy available at second trophic level is = 10x/100 = x/10 The energy available at third trophic level is = 10% of x/10 = x/100 The energy available at fourth trophic level is = 10% of x/100 = x/1000 Energy of fourth trophic level given is 5 KJ x/1000 = 5 KJ x = 5000 KJ Q10. In a food chain, the third trophic level is always occupied

Class 10 Maths Chapter 10 Circle NCERT Solutions CBSE Board
Class 10 Maths

Class 10 Maths Chapter 10 Circle NCERT Solutions CBSE Board

Class 10 Maths Chapter 10 Circle NCERT Solutions is an important chapter for students preparing for the Class 10 CBSE Board Examination. The NCERT textbook should be at the centre of your Mathematics preparation because it helps you understand the fundamental concepts, theorems, diagrams and methods that form the foundation of many examination questions. Simply completing the NCERT exercises once is not enough. Students should revise the chapter repeatedly and make NCERT Mathematics a part of their regular revision cycle. A good revision cycle can be: learn the concept → solve NCERT examples → attempt NCERT exercise questions without seeing the solution → check your mistakes → revise the concept → solve the question again → move towards PYQs and sample papers. When you follow this cycle regularly, the concepts become stronger and you become more confident in solving questions independently. The Class 10 Maths NCERT Solutions provided on this page are meant to support your learning when you are unable to understand a question or want to check your method after making your own attempt. Do not make the mistake of reading every solution directly. First take your notebook, try the question yourself, and only then use the solution for verification and learning. Repeated revision of NCERT questions can help you improve your accuracy, understanding and ability to present mathematical solutions properly in the examination. Therefore, make a habit of returning to NCERT again and again instead of studying the chapter only once. Connecting Class 10 Circles with What You Studied in Class 9 Before beginning Class 10 Maths Chapter 10 Circles, stop for a moment and remember what you studied about circles in Class 9 Mathematics. You have already developed an important foundation in the previous class. In Class 9, you studied concepts related to chords of a circle and the angle subtended by a chord at the centre, along with other basic properties of circles. Those ideas are not left behind; they become useful as you move into the more advanced concepts of Class 10. In Class 10, you will take your understanding of circles one step further. You will study important concepts and theorems related to tangents to a circle, the relationship between a tangent and the radius at the point of contact, properties involving chords and tangents, and circles circumscribed around quadrilaterals. You will also learn how these properties are used to solve mathematical problems and prove geometrical statements. So, do not approach this chapter as something completely new. Think of it as a continuation of your Class 9 learning. The concepts you studied earlier about chords and angles at the centre will help you connect with the new ideas introduced in Class 10. Whenever you come across a theorem or a diagram, try to recall what you already know about circles. This connection between Class 9 and Class 10 concepts can make the chapter easier to understand and remember. While studying the chapter, pay special attention to the figures, given information, construction of the argument, theorem being applied and final conclusion. In geometry, understanding the diagram and the relationship between different parts of the figure is often just as important as knowing the theorem. Use these Class 10 Maths Chapter 10 Circles NCERT Solutions CBSE Board as a learning and revision tool—not as a shortcut. First attempt every question yourself, then check the solution, identify your mistakes and revise the related concept. With repeated NCERT practice and proper revision, you can build a strong foundation for solving CBSE Board examination questions, previous-year questions and sample papers with confidence. Watch Class 10 Maths Chapter 10 Circles NCERT Solutions Now it is time to put your understanding into practice. Before watching the video below, take your Class 10 Maths NCERT textbook and notebook and try to solve the questions from Chapter 10 – Circles yourself. If you are watching the video on a particular exercise, pause the video when the question appears and solve it independently before continuing. After making your attempt, watch the complete solution carefully. Compare your method with the explained solution and pay attention to the theorem used, logical steps, calculations, diagrams and final answer. If you make a mistake, don’t worry—identify it, understand why it happened, and solve the question again. The video below provides a step-by-step explanation of the Class 10 Maths Chapter 10 Circles NCERT Solutions, helping you revise the chapter, strengthen your concepts and prepare more confidently for the CBSE Board Examination. Remember: Don’t just watch the solution—pause, solve, compare and learn. Exercise 10.1 Q1. How many tangents can a circle have? Ans.A circle has infinite points and through each point a tangents can be drawn so a circle can have infinite tangents. tangents at various points Q2.Fill in the blanks: (i)A tangent to a circle intersects it in ……..point(s) (ii)A line intersecting a circle in two points is called a ……… (iii)A circle can have ……….parallel tangents at the most. (iv)The common point of a tangent to a circle and the circle is called……. Ans. (i) A tangent to a circle intersects it in one point. (ii)A line intersecting a circle in two points is called a secant. (iii)A circle can have two parallel tangents at the most. (iv)The common point of a tangent to a circle and the circle is called the contact point. Q3.A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (A)12 cm(B)13 cm(C)8.5 cm(D) √(119) cm Ans.As we know OP⊥ PQ, because P is the contact point of the circle , PQ is the tangent on the circle and OP is the radius of circle. O P Q 5 cm12cm ΔOPQ is the right triangle So, OQ² = OP² + PQ² PQ² = OQ² – OP² PQ² = 12² – 5² PQ² = 144 – 25 =119 PQ =√119 Hence the length of PQ is√119 cm Class

Class 10 Maths CBSE Board Exam Complete Preparation
CBSE Maths Previous Years Question Papers, CBSE Sample Papers, Class 10 CBSE Maths Important Questions, Class 10 CBSE Maths MCQs, Class 10 Maths, Class 10 Maths Sample Paper

Class 10 Maths CBSE Board Exam Preparation

Class 10 Maths CBSE Board Exam Complete Preparation Preparing for the Class 10 Maths CBSE Board Exam requires more than simply completing the textbook. Students need a systematic combination of NCERT Solutions, previous year question papers, PYQs, sample papers, important questions, repeated questions, formulas and important mathematical concepts. This Class 10 Maths CBSE Board Exam Complete Preparation guide brings all these resources together in one place. You can use the links below to study chapter-wise, revise important concepts, practise board-level questions and test your preparation with sample and previous year papers. Whether you are preparing for CBSE Class 10 Maths Basic or Standard, this page can serve as your central preparation hub. Class 10 Maths CBSE Board Exam Preparation Resources Use the following resources according to your stage of preparation. 1. Class 10 Maths NCERT Solutions NCERT Mathematics is the foundation of Class 10 CBSE Maths preparation. Students should first understand the concepts and practise the questions given in the textbook. Our chapter-wise Class 10 Maths NCERT Solutions provide step-by-step explanations to help students understand the correct method of solving questions. 👉 Class 10 Maths NCERT Solutions – Chapter-wise You can use these solutions while completing each chapter and checking your answers. 2. Class 10 Maths Important Concepts Before solving difficult questions, it is important to understand the basic concepts and formulas of every chapter. Revise important concepts such as: Class 10 Maths Important Concepts | CBSE Board 1. Real Numbers 2. Polynomials 3. Pair of Linear Equations in Two Variables 4. Quadratic Equations 5. Arithmetic Progressions 6. Triangles 7. Coordinate Geometry 8. Introduction to Trigonometry 9. Some Applications of Trigonometry 10. Circles 11. Areas Related to Circles 12. Surface Areas and Volumes 13. Statistics 14. Probability This section is especially useful for students who find certain chapters difficult or need quick revision before solving questions. 3. Class 10 Maths Important Formulas Formula revision can save valuable time during the board examination. Students should maintain a chapter-wise formula revision list and practise applying each formula to different types of questions. Important formulas include: Revise the formulas regularly instead of trying to memorise everything immediately before the examination. Class 10 Maths Formulas – Chapter-Wise Formula Sheet Complete Class 10 CBSE & NCERT Mathematics formulas for all 14 chapters. Use this formula sheet for quick revision, board exam preparation, and practice. 1. Real Numbers Euclid’s Division Lemma a = bq + r, where 0 ≤ r < b Fundamental Theorem of Arithmetic Every composite number can be expressed as a product of primes, and this factorisation is unique apart from the order of the factors. HCF and LCM For two positive integers a and b: HCF(a, b) × LCM(a, b) = a × b Terminating Decimal Condition If a rational number is written in lowest form as p/q, its decimal expansion terminates if: q = 2m × 5n 2. Polynomials Quadratic Polynomial For p(x) = ax2 + bx + c, if α and β are its zeroes: α + β = −b/a αβ = c/a Cubic Polynomial For p(x) = ax3 + bx2 + cx + d, if α, β and γ are its zeroes: α + β + γ = −b/a αβ + βγ + γα = c/a αβγ = −d/a Division Algorithm Dividend = Divisor × Quotient + Remainder 3. Pair of Linear Equations in Two Variables General Form a1x + b1y + c1 = 0 a2x + b2y + c2 = 0 Conditions for Solutions Unique solution: a1/a2 ≠ b1/b2 No solution: a1/a2 = b1/b2 ≠ c1/c2 Infinitely many solutions: a1/a2 = b1/b2 = c1/c2 Cross-Multiplication Formula For equations: a1x + b1y + c1 = 0 a2x + b2y + c2 = 0 x/(b1c2 − b2c1) = y/(c1a2 − c2a1) = 1/(a1b2 − a2b1) 4. Quadratic Equations Standard Form ax2 + bx + c = 0, where a ≠ 0 Quadratic Formula x = (−b ± √(b2 − 4ac)) / 2a Discriminant D = b2 − 4ac D > 0: Two distinct real roots D = 0: Two equal real roots D < 0: No real roots Relation Between Roots and Coefficients If α and β are the roots: α + β = −b/a αβ = c/a Equation from Given Roots If α and β are roots: x2 − (α + β)x + αβ = 0 5. Arithmetic Progressions Common Difference d = a2 − a1 nth Term an = a + (n − 1)d Sum of First n Terms Sn = n/2 [2a + (n − 1)d] Also: Sn = n/2 (a + l) where l is the last term. Last Term l = a + (n − 1)d 6. Triangles Basic Proportionality Theorem If a line is drawn parallel to one side of a triangle, it divides the other two sides proportionally. AD/DB = AE/EC Similarity Criteria AAA – Angle Angle Angle SAS – Side Angle Side SSS – Side Side Side Areas of Similar Triangles If two triangles are similar: Area(△ABC) / Area(△DEF) = (AB/DE)2 Pythagoras Theorem In a right-angled triangle: Hypotenuse2 = Perpendicular2 + Base2 7. Coordinate Geometry Distance Formula For points A(x1, y1) and B(x2, y2): AB = √[(x2 − x1)2 + (y2 − y1)2] Section Formula If P divides AB internally in the ratio m:n: P = ((mx2 + nx1)/(m+n), (my2 + ny1)/(m+n)) Midpoint Formula ((x1 + x2)/2, (y1 + y2)/2) Area of Triangle Area = 1/2 |x1(y2 − y3) + x2(y3 − y1) + x3(y1 − y2)| 8. Introduction to Trigonometry Trigonometric Ratios Ratio Formula sin θ Perpendicular / Hypotenuse cos θ Base / Hypotenuse tan θ Perpendicular / Base cosec θ Hypotenuse / Perpendicular sec θ Hypotenuse / Base cot θ Base / Perpendicular Reciprocal Relations sin θ = 1/cosec θ cos θ = 1/sec θ tan θ = 1/cot θ Quotient Relations tan θ = sin θ / cos θ cot θ = cos θ / sin θ Trigonometric Identities sin2θ + cos2θ = 1 1 + tan2θ = sec2θ 1 + cot2θ = cosec2θ 9. Some Applications of

Class 9 Maths Ganit Manjari Chapter 3 The World of Numbers Solutions
Class 9 Maths, Class 9 Maths Ganit Manjari NCERT Solutions

Class 9 Maths Ganit Manjari Chapter 3 The World of Numbers Solutions

Class 9 Maths Ganit Manjari Chapter 3 – The World of Numbers Solutions Chapter 3 – The World of Numbers is an important chapter in Class 9 Maths Ganit Manjari. It helps students explore numbers, their properties, relationships and patterns through a variety of mathematical questions. The chapter encourages students to develop logical thinking and apply number concepts while solving problems. The chapter contains multiple exercises, and each exercise focuses on different aspects of the concepts introduced in The World of Numbers. Students should practise all the exercises carefully because they provide opportunities to understand the concepts, improve calculation skills and develop systematic problem-solving methods. Class 9 Maths Ganit Manjari Chapter 3 – The World of Numbers Class 9 Maths Ganit Manjari Chapter 3 – The World of Numbers introduces students to the fascinating world of numbers and their different forms. This chapter builds concepts starting from natural numbers and integers and gradually moves towards rational numbers, irrational numbers and real numbers. Students also explore number patterns, operations on numbers, representation of rational numbers on the number line, and decimal expansions. The chapter contains Exercise 3.1, Exercise 3.2, Exercise 3.3, Exercise 3.4 and Exercise 3.5, followed by the End-of-Chapter Exercises. Each exercise focuses on different aspects of the number system and provides opportunities to develop mathematical reasoning and problem-solving skills. In this post, you will find Class 9 Maths Ganit Manjari Chapter 3 solutions covering all the exercise sets as well as the End-of-Chapter Exercises. The complete video playlist is provided below so that students can follow the solutions step by step and revise the entire chapter conveniently. Exercise-wise Coverage Exercise Set 3.1 – Natural Numbers and Number Patterns Exercise 3.1 introduces students to the human need for counting and the development of natural numbers.The questions connect mathematics with historical examples such as Lothal and the Ishango bone.Students work with practical counting situations and identify patterns in numbers.The exercise also explores prime numbers and asks students to recognise their patterns.It introduces the idea of closure of natural numbers under different operations, particularly subtraction.Overall, this exercise builds the foundation for understanding how the number system developed and how natural numbers behave. Exercise Set 3.2 – Integers and Operations Exercise 3.2 develops the concept of integers, including positive numbers, negative numbers and zero.The questions use familiar situations such as temperature, profit, loss, debt and fortune to explain positive and negative quantities.Students practise addition, subtraction, multiplication and division involving integers.The exercise also introduces Brahmagupta’s rules for operating with positive and negative numbers.Special attention is given to understanding why subtracting a negative number is equivalent to adding a positive number.This exercise helps students connect the rules of integers with real-life situations. Exercise Set 3.3 – Rational Numbers and Their Properties Exercise 3.3 focuses on rational numbers and their basic operations and properties.Students learn to identify and prove when two rational numbers are equal using simplification or cross-multiplication.The exercise includes addition, subtraction, multiplication and division of rational numbers.It also gives ractice with the distributive property and its application to rational numbers.Several questions require students to simplify expressions and verify mathematical statements step by tep.Overall, this exercise strengthens students’ computational skills and develops a clear understanding of rational-number operations. Exercise Set 3.4 – Rational Numbers on the Number Line Exercise 3.4 takes rational numbers from calculations to their geometrical representation on the umber line.Students practise locating positive and negative rational numbers, including mixed numbers, on a single number line.The exercise also asks students to find rational numbers lying between two given rational numbers.Students solve problems involving addition and subtraction of rational numbers and their applications in everyday situations.An important idea developed here is that there are infinitely many rational numbers between any two rational numbers.The exercise therefore helps students understand both the numerical and visual nature of rational numbers. Exercise Set 3.5 – Decimal Expansions, Irrational Numbers and Cyclic Patterns Exercise 3.5 brings together several important ideas about rational and irrational numbers and decimal expansions.Students determine whether rational numbers have terminating or non-terminating repeating decimal expansions by examining the prime factors of their denominators.They also use long division to investigate repeating patterns, including the fascinating cyclic behaviour of numbers such as 1/13.The exercise asks students to classify numbers as rational or irrational and understand why some decimal expansions never terminate or repeat.Students also explore the result that 0.9999… is exactly equal to 1 using algebra.The final questions encourage students to investigate other reciprocals that produce interesting cyclic repeating decimals. End-of-Chapter Exercises – Complete Revision of “The World of Numbers” The End-of-Chapter Exercises provide a comprehensive revision of the major concepts covered throughout Chapter 3.They bring together questions related to rational numbers, decimal expansions, irrational numbers and the real number system.Students are required to apply concepts rather than simply recall definitions or rules.The questions provide an opportunity to practise calculations, representations and reasoning based on different parts of the chapter.These miscellaneous questions are especially useful for checking whether students can connect concepts learned across Exercises 3.1 to 3.5.Completing this section after all the individual exercises can help students revise the entire chapter and identify areas that need further practice. Frequently Asked Questions – Class 9 Maths Chapter 3 The World of Numbers 1. What is the name of Chapter 3 in Class 9 Maths Ganit Manjari?The name of Chapter 3 in Class 9 Maths Ganit Manjari is “The World of Numbers.” The chapter develops students’ understanding of different types of numbers and their properties. 2. What topics are covered in Class 9 Maths Chapter 3 The World of Numbers?Chapter 3 covers important concepts related to natural numbers, integers, rational numbers, irrational numbers and real numbers. It also discusses number patterns, operations on numbers, decimal expansions, rational numbers on the number line and interesting cyclic patterns. 3. How many exercises are there in Chapter 3 The World of Numbers?The chapter contains five main exercise sets: Exercise 3.1, Exercise 3.2, Exercise 3.3, Exercise 3.4 and Exercise 3.5. After these, there is an End-of-Chapter Exercises section containing questions based

Class 10 Maths Chapter 5 Arithmetic Progressions Most Important Questions
Class 10 CBSE Maths Important Questions, Class 10 Maths

Class 10 Maths Chapter 5 Arithmetic Progressions Most Important Questions

Class 10 Maths Most Important Questions Chapter 5 Arithmetic Progressions are designed to help students prepare for an important chapter that is regularly tested through questions based on the nth term, common difference, sum of terms, consecutive terms, and real-life applications. Practising Class 10 Maths Chapter 5 Important Questions helps students strengthen their understanding of Arithmetic Progressions, improve problem-solving skills, and become familiar with the different types of questions that can be asked in the CBSE Board Examination. Regular practice of Class 10 Maths Most Important Questions also helps students identify important concepts, revise formulas effectively, improve calculation accuracy, and develop confidence in solving both direct and application-based questions within the examination time. For students preparing for the CBSE Class 10 Maths Board Exam, practising different question patterns is particularly useful. Instead of learning only the formulas, students should understand when and how each formula is applied. This post provides 50 important Arithmetic Progressions PYQ-based questions for practice. The questions cover different levels, from basic formula-based questions to application and higher-order problems. Important Formulas of Arithmetic Progressions Before attempting the questions, revise the following important formulas of Arithmetic Progressions: nth term: an = a + (n – 1)d Sum of the first n terms: Sn = n/2 [2a + (n – 1)d] Sum when the last term is known: Sn = n/2 (a + l) Condition for three numbers a, b and c to be in AP: 2b = a + c Here, a is the first term, d is the common difference, n is the number of terms, and l is the last term. Watch the Complete Video Solution Reading questions is useful, but watching the complete step-by-step solution can help you understand how to approach different types of Arithmetic Progressions problems. I have also explained the important questions in my YouTube video. Before watching the solution, try solving each question yourself. If you get stuck, watch the explanation and then solve the question again without looking at the solution. Class 10 Maths Chapter 5 – Arithmetic Progressions Most Important Questions Tip: Pause the video before each question and give yourself a few minutes to solve it. This will make your practice much more effective. 50 Most Important Arithmetic Progressions PYQ-Based Questions 50 Important Arithmetic Progressions PYQ-Based Questions Question 1 Find the 20th term of the arithmetic progression 3, 7, 11, 15, … . Question 2 Find the common difference of the AP 15, 12, 9, 6, … . Question 3 Find the 15th term of the AP 8, 13, 18, 23, … . Question 4 Which term of the AP 21, 18, 15, 12, … is equal to -81? Question 5 Find the 25th term of the AP 5, 8, 11, 14, … . Question 6 Determine the common difference and the 10th term of the AP 2, 7, 12, 17, … . Question 7 Find the 18th term of the AP -5, -2, 1, 4, … . Question 8 Which term of the AP 3, 8, 13, 18, … is 78? Question 9 Find the number of terms in the AP 7, 13, 19, …, 127. Question 10 Find the 12th term from the end of the AP 4, 9, 14, …, 109. Question 11 If the nth term of an AP is 4n – 7, find its first term and common difference. Question 12 If the 7th term of an AP is 20 and the 13th term is 38, find the first term and common difference. Question 13 If the 5th term of an AP is 17 and the 11th term is 35, find the 20th term. Question 14 If the 10th term of an AP is 30 and its common difference is 3, find the first term. Question 15 If the 18th term of an AP is 53 and the first term is 2, find the common difference. Question 16 Find the sum of the first 20 terms of the AP 3, 7, 11, 15, … . Question 17 Find the sum of the first 25 terms of the AP 2, 5, 8, 11, … . Question 18 Find the sum of the first 30 terms of the AP 10, 15, 20, 25, … . Question 19 Find the sum of all multiples of 7 lying between 10 and 100. Question 20 Find the sum of all two-digit natural numbers which are divisible by 3. Question 21 Find the sum of all multiples of 5 between 50 and 200. Question 22 Find the number of terms and the sum of the AP 6, 10, 14, …, 102. Question 23 Find the number of terms and the sum of the AP 18, 15, 12, …, -48. Question 24 Find the sum of the first 15 terms of the AP 20, 17, 14, 11, … . Question 25 Find the sum of the first 40 positive odd integers. Question 26 Find three consecutive terms of an AP whose sum is 27 and whose product is 693. Question 27 Find three numbers in AP whose sum is 24 and whose product is 440. Question 28 Find three consecutive terms of an AP whose sum is 30 and whose product is 910. Question 29 If 2x + 3, 4x + 1 and 6x – 1 are consecutive terms of an AP, find x. Question 30 If x + 2, 3x + 2 and 5x – 4 are consecutive terms of an AP, find x. Question 31 If 2x, x + 6 and 3x + 2 are consecutive terms of an AP, find x. Question 32 If a, b and c are three consecutive terms of an AP, prove that 2b = a + c. Question 33 If a, b and c are three consecutive terms of an AP, show that a + c = 2b. Question 34 If the first term of an AP is 5 and the common difference is 4, find the sum of its first 35 terms. Question 35 If the first term of an

creat a feaured image size 1200 x 675 for-Most Important Questions for Class 10 Maths Chapter 4 – Quadratic Equations CBSE 2026-27
Class 10 CBSE Maths Important Questions, Class 10 Maths

Class 10 Maths Chapter 4 Quadratic Equations Most Important Questions

Quadratic Equations is an important chapter in Class 10 Maths, and Class 10 Maths Chapter 4 Quadratic Equations Most Important Questions are an essential part of preparation for the CBSE Board Examination. Questions from this chapter can be asked in different forms, including MCQs, short-answer questions, long-answer questions and application-based problems.Class 10 Maths Most Important Questions are highly valuable for CBSE Board Exam preparation because they help students focus on frequently asked concepts, important question patterns, and exam-oriented practice. In this chapter, students learn important concepts such as formation of quadratic equations, factorisation, completing the square, the quadratic formula, discriminant and the nature of roots. Word problems based on numbers, ages, speed, distance and dimensions are also important from the examination point of view. To help students prepare effectively, we have compiled 50 most important questions from Class 10 Maths Chapter 4 – Quadratic Equations. These include 20 questions based on the NCERT Class 10 Maths textbook and 30 questions based on important CBSE previous-year question patterns. The questions have been selected to provide practice across the major concepts and question types of the chapter. You can also watch the video:Class 10 Maths Chapter 4 Quadratic Equations Most Important Questions In addition to these 50 questions, we have also provided additional video solutions for Chapter 4 – Quadratic Equations. These videos contain further important questions with complete step-by-step solutions and are designed to give students extra practice beyond the questions listed here. Students can first practise the 50 important questions and then scroll down to watch the additional video solutions. This will help them understand different approaches to solving quadratic equations and improve their accuracy, speed and confidence for the CBSE Board Examination. Class 10 Maths Chapter 4 – Quadratic Equations: 50 Most Important Questions Quadratic Equations is an important chapter for the CBSE Class 10 Mathematics Board Examination. The following 50 questions are carefully selected for revision and practice. The first 20 questions are based on the concepts and question types given in the NCERT Class 10 Mathematics textbook, while the remaining 30 are based on important CBSE previous-year question patterns. Chapter 4 – Quadratic Equations Important topics: Standard form, factorisation, completing the square, quadratic formula, discriminant, nature of roots, and application-based problems. Part A – 20 Important Questions Based on NCERT Textbook Section 1 – Introduction and Formation of Quadratic Equations Check whether the following equations are quadratic equations: (i) (x + 1)2 = 2(x − 3) (ii) x2 + 3x = 4 (iii) x3 − 2×2 + x = 0 Give reasons for your answers. Determine whether the equation (x − 2)(x + 3) = x2 + 5 is a quadratic equation after simplifying it. The area of a rectangular plot is 528 m2. Its length is one metre more than twice its breadth. Form a quadratic equation to find the dimensions of the plot. The product of two consecutive positive integers is 306. Form the quadratic equation representing the situation and find the two integers. A mother is 26 years older than her son. Three years from now, the product of their ages will be 360. Form the required quadratic equation and find their present ages. Section 2 – Solving Quadratic Equations by Factorisation Solve by factorisation: x2 − 5x + 6 = 0 Solve by factorisation: 2×2 − 7x + 3 = 0 Solve: 3×2 − 2x − 8 = 0 using the factorisation method. Solve the quadratic equation: x2 − 9x + 20 = 0 Find the roots of: 4×2 − 4x − 15 = 0 by factorisation. Section 3 – Completing the Square and Quadratic Formula Solve the equation x2 + 6x + 5 = 0 by completing the square. Solve by completing the square: 2×2 + 5x − 3 = 0 Solve using the quadratic formula: 2×2 − 7x + 3 = 0 Solve using the quadratic formula: 3×2 + 5x − 2 = 0 Solve: 5×2 − 6x + 1 = 0 using the quadratic formula. Section 4 – Nature of Roots and Discriminant Find the discriminant of 2×2 − 4x + 3 = 0 and state the nature of its roots. Determine the nature of the roots of: 5×2 − 6x + 2 = 0 Find the value of k for which the equation x2 + kx + 9 = 0 has equal roots. Determine whether the equation 4×2 − 4x + 5 = 0 has real roots. Give a reason. Find the value of k so that the quadratic equation kx2 − 2x + 1 = 0 has two distinct real roots. Part B – 30 Important CBSE Previous-Year/PYQ-Based Questions These questions are selected from recurring CBSE Board Examination question patterns, including MCQs, short-answer questions, long-answer questions and application-based problems from Quadratic Equations. Section 1 – MCQ and 1-Mark Questions Which of the following represents a quadratic equation after simplification? (A) x2 + 2x + 1 = 0 (B) x + 5 = 0 (C) x3 + 2 = 0 (D) 2x + 7 = 0 The equation x + 1/x = 3,   x ≠ 0 can be converted into a quadratic equation. Write its standard form. For the equation x2 − 8x + 12 = 0, find the sum of its roots. If the discriminant of a quadratic equation is zero, what can you say about its roots? For what values of k will x2 − 4x + k = 0 have two distinct real roots? If the roots of x2 − 7x + 10 = 0 are α and β, find α + β and αβ. If one root of 2×2 + 5x + k = 0 is −1, find the value of k. Determine the nature of the roots of: x2 + 4x + 8 = 0 Which condition must be satisfied by the coefficients of ax2 + bx + c = 0 for it to be a quadratic equation? Find the value of k if the equation x2 + kx + 16 =

Class 10 Maths (Standard) Sample Paper Solution CBSE Board 2024–25
CBSE Sample Papers, Class 10 Maths

Class 10 Maths (Standard) Sample Paper Solution CBSE Board 2024–25

Preparing for the Class 10 CBSE Mathematics Standard exam requires more than simply memorising formulas. Practising a Class 10 Maths Standard Sample Paper Solution CBSE 2024-25 helps students understand the CBSE question-paper pattern, improve time management, revise important concepts, and learn how to present answers step by step. In this post, you can watch the complete video solution of the Class 10 Maths Standard Sample Paper 2024–25. The question paper is based on the official CBSE Sample Question Paper for Class X Mathematics Standard (Code 041). In the video, each question is solved step by step, making it easier for students to understand the correct method, important concepts, formulas, calculations, and answer presentation. The sample paper carries 80 marks and is designed for a 3-hour examination. Better heading before embedding the video Watch Class 10 Maths Standard Sample Paper 2024–25 Complete Solution Before watching the solution, try to solve the questions yourself. Then watch the video below to check your answers and understand the step-by-step methods used to solve each question. ▶️ Watch the complete video solution below: Class 10 Maths Standard Sample Paper 2024–25 – Overview The official CBSE Mathematics Standard Sample Question Paper contains 38 questions divided into five sections: A, B, C, D and E. All questions are compulsory, with internal choices provided at specified places. Section Question Numbers Type of Questions Marks Section A 1–20 MCQs & Assertion-Reason 20 Section B 21–25 Very Short Answer 10 Section C 26–31 Short Answer 18 Section D 32–35 Long Answer 20 Section E 36–38 Case Study Based 12 Total 38 Questions — 80 Marks The official sample paper specifies that Section A contains 20 questions of 1 mark each, Section B contains 5 questions of 2 marks each, Section C contains 6 questions of 3 marks each, Section D contains 4 questions of 5 marks each, and Section E contains 3 case-study questions of 4 marks each. Watch the Complete Video Solution If you want to understand how each question should be solved in the examination, watch the complete Class 10 Maths Standard Sample Paper Solution 2024–25 video. The solutions are explained step by step so that students can follow the correct method, understand the concepts involved, and learn how to present mathematical solutions properly in the CBSE examination. ▶️ Watch the complete video solution in Youtube-Click here Section A – MCQs and Assertion-Reason Questions Section A consists of 20 one-mark questions. Questions 1–18 are multiple-choice questions, while Questions 19 and 20 are Assertion-Reason based. This section tests concepts from different chapters, including: For example, the official marking scheme gives the answer to Question 1 as −6, 6, Question 2 as −5, and Question 4 as 7. Students should practise MCQs regularly because they can score these marks quickly when their concepts are clear. Class 10 Maths Most Important 100 MCQs for CBSE Board Exam Why Is Standard Mathematics Important? Standard Mathematics builds strong logical, analytical, and problem-solving skills that are useful far beyond the classroom. It forms an important foundation for many future careers and academic fields. In short, Standard Mathematics is not just about solving equations—it develops the logical thinking and analytical skills needed for many careers and future opportunities. Section A – MCQs and Assertion-Reason Questions Section A contains 20 questions carrying 1 mark each. These questions generally require students to identify the correct option, apply a concept quickly, or determine the correct relationship in Assertion-Reason questions. While solving 1-mark questions, read each question carefully and avoid spending too much time on a single question. Focus on the key concept, make accurate calculations, and select the answer logically. Section B – Very Short Answer Questions Section B contains five questions carrying 2 marks each. These questions generally require students to apply a formula, theorem, algebraic method, or mathematical concept. While solving 2-mark questions, avoid unnecessary calculations. Write the important steps clearly and arrive at the final answer logically. Section C – Short Answer Questions Section C contains six questions of 3 marks each. These questions require a more detailed solution than Section B. Students should focus on: Proper presentation can make your solution easier to evaluate. Section D – Long Answer Questions Section D consists of four questions carrying 5 marks each. These are important questions because they carry significant weightage. A good strategy is to divide your solution into logical steps rather than jumping directly to the answer. In geometry questions, draw neat figures and mention the relevant theorem or result wherever necessary. Section E – Case Study Based Questions Section E contains three case-study based questions carrying 4 marks each. Each case study contains sub-parts carrying 1, 1 and 2 marks respectively. These questions test whether students can apply mathematical concepts to a given real-life or contextual situation. When solving case-study questions: Important Instructions for the CBSE Maths Standard Sample Paper The official sample paper gives several important instructions. Students should remember that the examination duration is 3 hours, the maximum marks are 80, calculators are not allowed, and neat figures should be drawn wherever required. The paper also instructs students to take (\pi=\frac{22}{7}) wherever required unless stated otherwise. Why Should You Practise This Sample Paper? Solving the CBSE official sample paper before the examination can help you: The CBSE question-paper design for Mathematics Standard 2024–25 also included questions testing remembering, understanding, applying, analysing, evaluating and creating skills. How to Use This Sample Paper Effectively For the best results, do not immediately watch the solution after reading a question. First, try to solve the complete paper yourself under examination conditions. Keep the 3-hour time limit and avoid using a calculator. After completing the paper, compare your answers with the video solutions. Pay particular attention to questions where: This approach will help you turn your mistakes into revision points. Download the Official CBSE Sample Paper Students can also access the official CBSE Class X Mathematics Standard Sample Question Paper 2024–25 and its marking scheme from CBSE’s Academic website. The official sample paper is for

Class 10 Maths Most Important 100 MCQs for CBSE Board Exam ,Selected from Last years Question Papers
Class 10 CBSE Maths MCQs, Class 10 Maths

Class 10 Maths Most Important 100 MCQs for CBSE Board Exam

Preparing for the CBSE Class 10 Maths Board Exam? Practising important MCQs (Multiple Choice Questions) is an excellent way to revise concepts, formulas, theorems and calculation-based questions quickly. In this post, Future Study Point brings you a collection of Class 10 Maths Most Important MCQs with Answers, covering important concepts from the Class 10 Mathematics syllabus. These questions are useful for revision, school exams, pre-board exams and CBSE Board Exam preparation.Watch the video: To understand and practice these Class 10 Maths Most Important 100 MCQs for the CBSE Board Exam, scroll down and watch the complete video below. Class 10 Maths Important MCQs Selected from Last Years Question Papers 1. What type of number is √0.4? A) Natural B) Integer C) Rational D) Irrational Show Answer Answer: D) Irrational 2. Which of the following cannot be the unit digit of 8n, where n is a natural number? A) 4 B) 2 C) 0 D) 6 Show Answer Answer: C) 0 3. Which of the following quadratic equations has real and equal roots? A) (x + 1)2 = 2x + 1 B) x2 + x = 0 C) x2 − 4 = 0 D) x2 + x + 1 = 0 Show Answer Answer: A) (x + 1)2 = 2x + 1 4. If the zeroes of ax2 + bx + 2a/b are reciprocals of each other, then b is: A) 2 B) 1/2 C) −2 D) −1/2 Show Answer Answer: A) 2 5. The distance of the point (−3, −4) from the x-axis is: A) 3 B) 4 C) 5 D) 7 Show Answer Answer: B) 4 6. If two coins are tossed simultaneously, the probability of getting at least one head is: A) 1/4 B) 1/2 C) 3/4 D) 1 Show Answer Answer: C) 3/4 7. Two tangents are drawn from an external point P to a circle. If ∠P = 90° and the chord joining the points of contact has length 3√2 cm, the diameter of the circle is: A) 3√2 cm B) 6√2 cm C) 3 cm D) 6 cm Show Answer Answer: D) 6 cm 8. The equations 2x + 1 = 0 and 3y − 5 = 0 have: A) No solution B) Two solutions C) Infinitely many solutions D) A unique solution Show Answer Answer: D) A unique solution 9. In a right triangle, if sin B = 1/4, then sec B is: A) 4 B) √15/4 C) √15 D) 4/√15 Show Answer Answer: D) 4/√15 10. For two prime numbers p and q, the HCF is 1 and the LCM is p + q. Which option is correct? A) Both Assertion and Reason are true and Reason explains Assertion B) Both are true but Reason does not explain Assertion C) Assertion is true but Reason is false D) Assertion is false but Reason is true Show Answer Answer: D) Assertion is false but Reason is true 11. The HCF of 960 and 432 is: A) 48 B) 54 C) 72 D) 36 Show Answer Answer: A) 48 12. The natural number 2 is: A) Prime B) Composite C) Both prime and composite D) Neither prime nor composite Show Answer Answer: A) Prime 13. For every natural number n, the units digit of 6n is: A) 0 B) 6 C) 3 D) 2 Show Answer Answer: B) 6 14. If the graph of a polynomial f(x) does not intersect the x-axis, then the number of zeroes is: A) 0 B) 1 C) 2 D) 4 Show Answer Answer: A) 0 15. If two linear equations are represented by coincident lines, the number of solutions is: A) One B) Two C) Zero D) Infinitely many Show Answer Answer: D) Infinitely many 16. The common difference of the AP 2√2, 3√2, 4√2, … is: A) √2 B) 1 C) 2√2 D) −√2 Show Answer Answer: A) √2 17. If △ABC ~ △DEF, DE = 2AB and BC = 8 cm, then EF is: A) 4 cm B) 8 cm C) 12 cm D) 16 cm Show Answer Answer: D) 16 cm 18. The midpoint of the line segment joining (5, −4) and (6, 4) lies on: A) x-axis B) y-axis C) Origin D) Neither axis Show Answer Answer: A) x-axis 19. A car is 10√3 m away from the base of a 30 m high tower. The angle of elevation of the top is: A) 30° B) 45° C) 90° D) 60° Show Answer Answer: D) 60° 20. Two tangents TP and TQ are drawn from T. If ∠POQ = 120°, then ∠PTQ equals: A) 60° B) 70° C) 80° D) 90° Show Answer Answer: A) 60° 21. If PA is tangent to a circle with centre O and ∠POB = 125°, then ∠APO is: A) 25° B) 65° C) 90° D) 35° Show Answer Answer: D) 35° 22. The length of the arc of a sector with radius 21 cm and central angle 60° is: A) 22 cm B) 44 cm C) 88 cm D) 11 cm Show Answer Answer: A) 22 cm 23. The hour hand of a clock sweeps through what angle between 7:00 a.m. and 8:10 a.m.? A) 17.5° B) 35/2° C) 35° D) 70° Show Answer Answer: C) 35° 24. A solid hemisphere has diameter 2d. Its total surface area is: A) 3πd2 B) 2πd2 C) 1/2πd2 D) 3/4πd2 Show Answer Answer: A) 3πd2 25. If the mean of a data set is 12 and its mode is 21, its median is: A) 6 B) 13.5 C) 15 D) 14 Show Answer Answer: C) 15 26. A die is thrown once. The probability of obtaining a number other than 3 is: A) 1/6 B) 3/6 C) 5/6 D) 1 Show Answer Answer: C) 5/6 27. A leap year has 53 Mondays with probability: A) 1/7 B) 2/7 C) 5/7 D) 6/7 Show Answer Answer: B) 2/7 28. Consider p(y) = y2 + 4y + 3. The number of zeroes of this polynomial is: A) 0 B) 1 C) 2 D)

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