Class 9 Maths MCQs on Probabilty Chapter 15 with Solutions for CBSE Board Exam 2021-22
Class 9 Maths MCQs on probability chapter 15 is created here for helping the students of class 9 in preparation of their unit tests and CBSE exams. All MCQ questions are selected here as per the latest maths sample paper published by CBSE Board for 2021-22. MCQs on probability are selected as per the standard CBSE maths sample paper,so the study of these MCQs is mandatory for every student. All questions are explained here with the easiest method therefore every student can understand. You can also study other study inputs like science and maths NCERT Solutions.
MCQ’s on Real Numbers for Term 1 CBSE with Solutions
MCQ’s on Class 10 Maths Co-ordinate Geometry for Term 1 CBSE
Class 10 Maths MCQs with solutions -Chapter 6 Triangles
Class 10 Maths MCQ’s on Trigonometry for Term 1 CBSE with Solutions
Class 10 MCQ’s questions with solutions-Polynomial
Class 9 Maths MCQs on Probabilty Chapter 15 with Solutions for CBSE Board Exam 2021-22
Click for online shopping
Future Study Point.Deal: Cloths, Laptops, Computers, Mobiles, Shoes etc
Q1. If a dice is thrown in the air then its probability of getting an even number is:
(a) 2/3 (b) 1/3 (c) 1/2 (d) 1/4
Ans. When the dice is thrown once,then total possible outcomes are 1,2,3,4,5,6 (i.e 6)
The even numbers are 2,4,6
P(even number) = the number of even numbers/total possible outcomes = 3/6 = 1/2
Q2.If a dice is thrown in the air then the probabilty of getting at least 4 is:
(a) 2/3 (b) 3/4 (c) 1/2 (d) 1/3
Ans. (a) 2/3
When a dice is thrown once then total possible outcomes are 1,2,3,4,5,6 i.e 6
The outcomes which are at least 4 are 1,2,3,4 i.e 4
P(at least 4) = the numbers showing the digits at least 4/total possible outcomes = 4/6 =2/3
Q3. If two coin are thrown in the air then the probability of getting two heads is :
(a) 2/3 (b) 1/2 (c) 1/3 (d) 1/4
Ans. Total outcomes when two coins are thrown simultaneously are (HH),(TT),(TH),(HT)
Two heads are (HH) i.e 1
P(2 heads ) = number of two heads /total outcomes = 1/4
Q4.If three coins are thrown simultaneously then what is the probability of getting exactly three heads.
(a) 1/3 (b) 2/3 (c) 2/5 (d) 3/8
Ans. The outcomes when three coins are tossed simultaneously are (HHH),(TTT),(HHT),(TTH),(HTH),(THT),(THH),(HTT) [i.e 8]
The outcomes with exactly two heads are (HHT),(HTH),(THH) [i.e 3]
P( exaactly two heads) = the number of two heads/no. of total outcomes = 3/8
Q5. If the probabilty of raining a day is 0.25 then the probability of not raining is :
(a) 0.85 (b) 0.75 (c) 1/4 (d) 3/5
Ans. (b) 0.75
Let the event of raining is E
The probabilty of raining ,P(E) is 0.25
The probabilty of not raining is = 1 – 0.25 =0.75[P(E) + P(not E) = 1]
Q6.If a card is drawn from a dec of a 52 cards then the probabilty of getting a red card is:
(a) 1/2 (b) 1/4 (c) 3/4 (d) 4/5
Ans. (a) 1/2
The total number of cards are 52
The number of red cards are = 13 diamonds + 13 heart = 26
P(red card) = no. of red cards/total number of cards = 26/52 = 1/2
Q7.If a card is drawn from a well-suffled dec of 52 cards then the probability of getting an ace is:
(a) 1/13 (b) 2/13 (c) 1/2 (d) 1/4
Ans. (a) 1/13
The total number of cards are 52
The number of ace = 4
P(card is ace ) = no. of aces/total number of cards = 4/52 = 1/13
Q8. A fair dice is thrown once,then the probability of getting a composite number:
(a) 1/3 (b) 2/3 (c) 3/4 (d) 2/5
Ans. The total outcomes of the event are 1,2,3,4,5,6 (i.e 6)
The composite numbers are 2,4,6 (i.e 3)
P(getting a composite number) =no. of composite numbers/total outcomes = 3/6 = 1/2
Q9.The probabilty of occuring 53 sundays in a leap year is:
(a) 1/7 (b) 2/7 (c) 3/7 (d) 4/7
Ans. (a) 2/7
The total number of days in a leap year are 366
In 366 days there are 52 weeks and 2 days
The number of days which can make 53 sundays are =2
Total number of days in a week are = 7
P( no. of 53 sundays ) = no. of days which can make 53 sudays/total number of days in a week =2/7
Q10. The probabilty of choosing a girl out of 40 students of a class is 5/8,find the number of boys in the class.
(a) 20 (b) 15 (c) 30 (d) 26
Ans.(b) 15
Let the number of girls in the class are =x
Total student in a class are = 40
Probability of choosing a girl,P(G) = 5/8
P(G) = number of girls in the class /no. of total students in the class = x/40
x/40 = 5/8
x = 40 × (5/8) = 25
Number of boys = total students – number of girls =40 -25 = 15
You can compensate us by donating any amount of money for our survival
Our Paytm NO 9891436286
NCERT Solutions of class 9 science
CBSE Class 9-Question paper of science 2020 with solutions
CBSE Class 9-Sample paper of science
CBSE Class 9-Unsolved question paper of science 2019
NCERT Solutions of class 10 maths
CBSE Class 10-Question paper of maths 2021 with solutions
CBSE Class 10-Half yearly question paper of maths 2020 with solutions
CBSE Class 10 -Question paper of maths 2020 with solutions
CBSE Class 10-Question paper of maths 2019 with solutions
NCERT solutions of class 10 science
Solutions of class 10 last years Science question papers
CBSE Class 10 – Question paper of science 2020 with solutions
CBSE class 10 -Latest sample paper of science
NCERT solutions of class 11 maths
| Chapter 1-Sets | Chapter 9-Sequences and Series |
| Chapter 2- Relations and functions | Chapter 10- Straight Lines |
| Chapter 3- Trigonometry | Chapter 11-Conic Sections |
| Chapter 4-Principle of mathematical induction | Chapter 12-Introduction to three Dimensional Geometry |
| Chapter 5-Complex numbers | Chapter 13- Limits and Derivatives |
| Chapter 6- Linear Inequalities | Chapter 14-Mathematical Reasoning |
| Chapter 7- Permutations and Combinations | Chapter 15- Statistics |
| Chapter 8- Binomial Theorem | Chapter 16- Probability |
CBSE Class 11-Question paper of maths 2015
CBSE Class 11 – Second unit test of maths 2021 with solutions
NCERT solutions of class 12 maths
| Chapter 1-Relations and Functions | Chapter 9-Differential Equations |
| Chapter 2-Inverse Trigonometric Functions | Chapter 10-Vector Algebra |
| Chapter 3-Matrices |
