Class 10 Maths MCQ’s with Solutions -Areas Related to Circle for Term 1 CBSE Board 2021
Here we have selected few maths MCQ’s from the class 10 Maths chapter -Area related to circle for your prapartion of the CBSE Board exam Term-1 2021. All these MCQ questions are solved by an expert of maths as per the CBSE norms. Since maximum questions in your question paper of Term 1 will be out of your NCERT text book exercises so the practice of MCQ’s is mandatory for everybody for achieving excellent marks. The practice of NCERT questions is also necessary to clear your concept of the chapters and to gain proper understanding.
Class 10 Maths MCQ’s with Solutions -Areas Related to Circle for Term 1 CBSE Board 2021
Q1.Perimeter of sector of a circle whose centre of angle is 90° and radius 7 cm is
(a) 35 cm (b) 25 cm (c) 77 cm (d) 7 cm
Ans.(a) 35 cm
The length of the arc(l) corresponding to the sector of the circle with θ as a centre of angle is given by
l = (θ/360°)2πr
Here r = 7 cm, θ = 90°
l = (90°/360°)2×(22/7)7 = (1/4) ×44 = 11
Perimeter of the sector is = l+ r + r = 11 +2×7 = 11 +24 = 35 cm
Q2. The area of a circle that can be inscribed in a square of side 10 cm is
(a) 40π cm² (b) 30π cm² (c) 100π cm² (d) 25π cm²
Ans.(d) 25π cm²
If a circle is inscribed in a square, side of the square is equal to the diameter of the circle
Let the diameter of the circle is = 2r
∴ 2r = 10 ⇒ r= 5
Hence radius = 5 cm
Area of the circle is = πr² = π×5² = 25π
Q3.The perimeter of a sector of radius 5.2 cm is 16.4 cm ,the area of the sector is
(a) 31.2 cm² (b) 15 cm² (c) 15.6 cm² (d) 16.6 cm²
Ans. (b) 15.6 cm²
The perimeter of the sector is = 2r +l
Where l is the length of the arc corresponding to the sector of the circle
2×5.2 +l = 16.4
10.4 + l = 16.4
l = 16.4 -10.4 =6
The length of the arc(l) corresponding to the sector of the circle with θ as a centre of angle is given by
Area of the sector is = (1/2) lr
Area of the sector =(1/2) ×6×5.2 =15.6 cm²
Class 10 Maths MCQ’s with Solutions -Areas Related to Circle for Term 1 CBSE Board 2021
Q4.The perimeter of a circular and square fields are equal. If the area of the square field is 484 m² then the diameter of the circular field is
(a) 14 cm (b) 28 cm (c) 21 cm (d)7 cm
Ans.(b) 28 cm
Let the radius of circular field is r and side of square field is x
We are given
x² = 484
x = 22 cm
2πr = 4x
πr = 2x = 2×22 =44
(22/7) r = 44
r = (44 ×7)/22 = 14 cm
2r = 28 cm
Hence diameter of the circular field is 28 m
Q5.The area of the largest square that can be inscribed in a circle of radius 12 cm is
(a) 24 cm² (b) 249 cm² (c) 288 cm² (d) 196√2cm²
Ans.(c) 288 cm²
Let the side of the largest square is x
The diagonal must be the diameter of the circle since the square is inscribed in the circle
Diagonal and both sides will make right triangle
Diagonal = Diameter of the circle =2×12 = 24 cm
x² + x² = 24² = 576
2x² = 576
x² = 288
Area of the square = 288 cm²
Class 10 Maths MCQ’s with Solutions -Areas Related to Circle for Term 1 CBSE Board 2021
Q6.The area of the largest triangle that can be inscribed in a semicircle of radius r is
(a) r² (b) 2r² (c) r³ (d) 2r³
Ans.(a) r²
The base of the Lagest triangle inscribed in a semicircle is the diameter of the semicircle =2r
And the altitude of this triangle is = radius of the circle = r
Area of the required triangle = (1/2) Base ×Altitude = (1/2) 2r ×r = r²
Q7.The area (in cm²) of the circle that can be inscribed in a square of side 8
(a) 64π cm² (b) 16π cm² (c) 8π cm² (d) 32πcm²
Ans.(b) 16π cm²
The diameter of the circle inscribed in a square is the side of the square = 8 cm
The radius of the circle is = 8/2 = 4 cm
Area of the circle is πr² = π×4² = 16 π cm²
Class 10 Maths MCQ’s with Solutions -Areas Related to Circle for Term 1 CBSE Board 2021
Q8.A steel wire when bent in the form of a square encloses an area of 121 cm². If the same wire is bent in the form of a circle, then the circumference of the circle is
(a) 18 cm (b) 44 cm (c) 22 cm (d) 11 cm
Ans.(b) 44 cm
A steel wire when bent in the form of a square and then in the form of a circle,in both case its perimeter will be tha same, the area of square given to us is 121 cm²
Let the side of square is = x
x² = 121
x = 11 cm
The circumference of the circle is = Perimeter of the square = 4x
circumference of the circle is = 4×11 = 44 cm
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| Chapter 1-Sets | Chapter 9-Sequences and Series |
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| Chapter 3- Trigonometry | Chapter 11-Conic Sections |
| Chapter 4-Principle of mathematical induction | Chapter 12-Introduction to three Dimensional Geometry |
| Chapter 5-Complex numbers | Chapter 13- Limits and Derivatives |
| Chapter 6- Linear Inequalities | Chapter 14-Mathematical Reasoning |
| Chapter 7- Permutations and Combinations | Chapter 15- Statistics |
| Chapter 8- Binomial Theorem | Chapter 16- Probability |
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| Chapter 1-Relations and Functions | Chapter 9-Differential Equations |
| Chapter 2-Inverse Trigonometric Functions | Chapter 10-Vector Algebra |
| Chapter 3-Matrices | Chapter 11 – Three Dimensional Geometry |
| Chapter 4-Determinants | Chapter 12-Linear Programming |
| Chapter 5- Continuity and Differentiability | Chapter 13-Probability |
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| Chapter 7- Integrals | |
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