Class 10 Maths MCQ’S on Chapter 1 Real Numbers for Term-1 CBSE Board Exam 2021
Class 10 Maths MCQ’S on Chapter 1 Real Numbers for Term-1 CBSE Board Exam 2021 are created here for the preparation of Term 1 CBSE Board exam 2021. The practice of such MCQ questions is strictly required to every student because in Term 1 CBSE Board exam 2021 there will be 50 MCQ questions in which students have to solve 40 questions in 90 minutes . Each question is of 1 mark, so the average time is given to a question to solve it is 2.25 minutes, there may be a few of questions that will take more than 5 minutes, hence the practice of these MCQ questions is needed to every student.
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Q1. The decimal form of 229/(2^{3}×5^{6}×3^{3}) is
(a) Terminating (b) Non -recurring terminating (c) Recurring terminating decimal (d) None of these
Ans. (c) Recurring terminating decimal
The decimal form of any rational number is terminating if the factor of the denominator ( Q) in P/Q are of the form (2^{m}×5^{n}) where P and Q both are co-prime numbers and if the factors are other than of the form (2^{m}×5^{n}) then it is Recurrent and terminating decimal
Q2. After how many places of decimal will the decimal expansion of the number 37/(2^{3}×5^{2}) terminate ?
(a) 3 (b) 4 (c) 2 (d) 1
Ans.(a) 3
The given number is
37/(2^{3}×5^{2})
Multiplying the denominator and numerator by 5
(37×5)/(2^{3}×5^{2} ×5)
185/(2^{3}×5^{3}) =185/1000 = 0.185
Q3. A die is thrown once .The probability of getting a composite number is
(a) 1/3 (b) 1/6 (c) 1/2 (d) 2/3
Ans. The total number of outcomes when a die is throwen once are =6
The number of composite numbers are = 2(i.e 4,6)
P(outcome is composite number) = Number of composite numbers/Total number of outcomes =2/6 = 1/3
Q4.The product of rational and irrational number is
(a) rational (b) irrational (c) both of above (d) none of the above
Ans. The product of a rational number (i.e 2) and irrational number (i.e √2) is irrational (i.e 2√2)
Ans. (b) irrational
Q5. If b = 3 ,then any integer can be expressed as a
(a) 3q ,3q +1, 3q + 2 (b) 3q (c) none of the above (d) 3q +1
Ans.(a) 3q ,3q +1, 3q + 2
According to Euclid’s theorem any positive integer(a) can be written in the form of bq +r
a = bq +r where 0 ≤ r < b
We are given b =3
∴ 0 ≤ r< 3
The possible values of r are 0,1,2
The corresponding values of a are 3q,3q +1 and 3q +2
Q6. The HCF of 5^{30}and 5³ will be
(a)5^{30} (b) 125 (c) 1 (d) 5
Ans. (b) 125
The given numbers are
5^{30}=5×5×5×5^{27}
5³ = 5×5×5
HCF of the given numbers is 5×5×5 = 125
Q7.The product of three consecutive integers is divisible by
(a) 4 (b) 6 (c) no common factor (d) only one
Ans.(b) 6
Let three consecutive integers are 1,2 and 3
Their products = 1×2×3 = 6, which is divisible by 6, similarly we can other triplets ,their product is always divisible by 6
Class 10 Maths NCERT Solutions Exercise 1.1 and 1.2 Chapter 1 Real Numbers
Q8.LCM of the given number and ‘x’ where ‘y’ is multiple of ‘x’ is given by
(a) x (b) y (c) xy (d) x/y
Ans.(b) y
The given number is x and y is multiple of x
Let y = ax
LCM(x,y) = ax = y
Q9.There are 312 , 260 and 156 students in class X, XI and XII respectively. Buses are to be hired to take these students to a picnic. Find the maximum number of students who can sit in a bus if each bus takes equal number of students.
(a) 52 (b) 56 (c) 48 (d) 63
Ans.(a) 52
The number of students of X,XIand XII are 312, 260 and 156 respectively
The maximum students who can sit in a bus if each bus carries equal number of the students = HCF of the numbers 312,260 and 156
312 = 2×2×2×13 ×3
260 = 2×2×5×13
156 = 3×2×2×13
HCF = 2×2×13 = 52
Q10.There is a circular path around a sports field. Priya takes 18 minutes to drive one round of the field. Harish takes 12 minutes. Suppose they both start at the same point and at the same time and go in the same direction. After how many minutes will they meet?
(a) 36 minutes (b) 18 minutes (c) 6 minutes (d) They will not meet
Ans.(c) 6 minutes
Priya takes to drive one round of circular path in 18 minutes and Harish takes 12 minutes
If they start at the same point then they will meet after a time period equivalent to the LCM of 18 and 12
18 = 3×3×2 and 12 = 2×2×3
The LCM = 3×2 = 6
Q11.Three farmers have 490 kg, 588 kg and 882 kg of wheat respectively. Find the maximum capacity of a bag so that the wheat can be packed in exact number of bags.
(a) 98 kg (b) 290 kg (c) 200 kg (d) 350 kg
Ans.(a) 98 kg
It is given that three farmers have 490 kg, 588 kg and 882 kg of wheat respectively
Maximum capacity of a bag so that the wheat can be packed is equivalent to their HCF of the numbers 490 , 588 and 882
490 = 7×7×2×5
588 = 2×2×7×7×3
882 = 2×3×3×7×7
HCF(490 , 588 , 882) = 2×7×7 = 98
Q12. m² – 1 is divisible by 8 ,if m is
(a) an even number (b) an odd number (c) a natural number (d) a whole number
Ans.(b) an odd number
The expression given to us is m² – 1
For m =1 the value of m² – 1 =1² -1 = 0 ,divisible by 8
For m =2 the value of m² – 1 =2²-1 =3 ,not divisible by 8
For m =3 the value of m² – 1 =3² -1 = 8 ,divisible by 8
Hence m should be odd number
The purpose of these solutions of MCQ questions based on chapter 1 -Real numbers Class 10 Maths NCERT is to aware all the students about the type of questions which are going to be asked in Term 1 CBSE Board exam 2021 .We hope you would have liked the solutions of these MCQ ,if it is so subscribe us so that we could bring other input study material for your future examination.
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