Class 9 Maths MCQs Polynomial with Solutions - Future Study Point

Class 9 Maths MCQs Polynomial with Solutions

class 9 maths MCQ Polynomial

Class 9 Maths MCQs -Chapter 2 Polynomial with Solutions

class 9 maths MCQ Polynomial

Class 9 Maths MCQs Polynomial with Solutions are created for the purpose of helping the class 10 students for the preparation of Term 1 CBSE Board exam 2021. The practice of these MCQs are required to every students because the pattern of the CBSE Board exam has changed and all the questions in the question paper are of MCQs types . All the questions of chapter 2 Polynomial are selected here as per the CBSE sample paper of maths published by CBSE.The solutions of these MCQs of the chapter Polynomial are created here as per the CBSE norms and explained here in easiest way so every students can understand the solutions.

MCQ’s on Real Numbers for Term 1 CBSE with Solutions

MCQ’s on Class 10 Maths Co-ordinate Geometry for Term 1 CBSE

Class 10 Maths MCQs with solutions -Chapter 6 Triangles

Class 10 Maths MCQโ€™s on Trigonometry for Term 1 CBSE with Solutions

Class 10 MCQ’s questions with solutions-Polynomial

Class 9 Maths MCQs -Chapter 2 Polynomial with Solutions

Click for online shopping

Future Study Point.Deal: Cloths, Laptops, Computers, Mobiles, Shoes etc

Q1. The value of the polynomial P(x) = 5xยณ – 3xยฒ + 7x – 10,when x = -1 is:

(a) 7ย  ย  ย (b) 17ย  ย  ย  ย (c) -18ย  ย  ย  (d) -25

Ans. The given polynomial P(x) =5xยณ – 3xยฒ + 7x – 10

The value of the polynomial when x =-1

P(-1) = 5(-1)ยณ -3(-1)ยฒ +7(-1) -10 = -5 -3 -7 -10 =-25

Q2.One of theย  zeroes of the polynomial P(x) = xยฒ – 1 are :

(a) -1ย  ย  ย  ย (b) -2ย  ย  ย  ย (c) 0ย  ย  ย  (d) -3

Ans. (a) -1

The given polynomial is P(x) = xยฒ – 1

P(x) = xยฒ – 1 = 0

(x +1)(x -1) = 0

x = -1 and x = 1

Q3.The product of ( x + 1/x)(x -1/x)(xยฒ + 1/xยฒ) is :

(a) (x – 1/x)ยณย  ย  ย  ย (b) xย  + 1/xยณย  ย  ย  ย (c) ย x4-1/ x4ย  ย  (d) ย x4+ 1/ x4

Ans. The given expression is

(x + 1/x)(x -1/x)(xยฒ + 1/xยฒ)

= (xยฒ – 1/xยฒ)(xยฒ+1/xยฒ) [i.e aยฒ -bยฒ = (a +b)(a – b)]

= ( x4-1/ x4) [ i.e aยฒ – bยฒ = (a + b)( a – b)]

Q4.Ifย  x/yย  + y/x = -1 (x,y โ‰  0), then the value of xยณ – yยณย is

(a) 1ย  (b) (x -y)(xยฒ – yยฒ +1)ย  ย  ย (c) 0ย  ย (d) -1/2

Ans.(c) 0

The given equation is

x/y + y/x = -1

(xยฒ + yยฒ)/xy = -1

xยฒ + yยฒ = -xy….(i)

Cubing both sides

The value of xยณ – yยณ = (x -y)(xยฒ +yยฒ + xy)

Putting the value from equation (i)

xยณ – yยณ = ( x – y)( -xy +xy) =0

Q5. The value of 625ยฒ – 575ยฒย ย is

(a) 50000ย  ย  ย  ย  ย (b)30000ย  ย  ย  ย  ย  ย (c)60000ย  ย  ย  ย  ย  ย  (d) 40000

Ans.

625ยฒ – 575ยฒ = (625 + 575)(625 – 575) = 1200 ร— 50 =60000

Q6. If xยฒ + kx + 6 = ( x +1)( x – 3),then value of k is

(a) 1ย  ย  ย  ย  ย  ย  (b) -1ย  ย  ย  ย  ย  (c) 2ย  ย  ย  ย  ย  (d) -1

Ans. The given equation is

xยฒ + kx + 6 = (x +2)( x +3)

xยฒ + kx + 6 = xยฒ + (2+3)x + 2ร—3 = xยฒ + 5x +6

On comparing LHS and RHS

k = 5

Q7. The coefficient of xยณ in ( 2xยฒ + 2x)(5xยณ – 9xยฒ) is:

(a) -15ย  ย  ย  ย (b) -18ย  ย  ย  ย (c) 27ย  ย  ย  ย  (d) -28

Ans. (2xยฒ + 2x)(5xยณ -9xยฒ) for getting the coefficient of xยณ,multiplying 2x and -9xยฒ i.e 2xร—-9xยฒ = -18xยณ

Hence the coefficient of xยณ is -18

Q8. Find the remainder when the polynomial 3xยณ – 8xยฒ + 17x + 4 is divided by x:

(a) 2ย  ย  ย  ย  (b) -4ย  ย  ย  ย  ย (c) 4ย  ย  ย  ย  (d) 0

Ans.(c) 4

The given polynomial is 3xยณ – 8xยฒ + 17x + 4

Putting the value x = 0

3(0)ยณ – 8(0)ยฒ +17(0) + 4 = 4

Q9.If 2x + y + 3z = 0, then the value ofย  8xยณ + yยณ + 27zยณ is :

(a) 18xyzย  ย  ย  ย  (b) -18xyzย  ย  ย  ย  (c) 36xyzย  ย  ย  ย  (d) -36xyz

Ans.(a) 18xyz

The given equation is

2x + y + 3x = 0

Applying the identity

aยณ + bยณ +cยณ – 3abc = (a + b +c)(aยฒ + bยฒ + cยฒ – ab – bc -ac)

(2x)ยณ + yยณ + (3z)ยณ – 3ร—2xร—3z = ( 2x + y +3z)(4xยฒ + yยฒ + 9zยฒ -2xy – 3yz – 6xz)

Putting the value of 2x + y +3z = 0

8xยณ + yยณ + 27zยณ = 0

Q10. If area of the rectangle is 4xยฒ + 4x – 3,then its possible diensions are :

(a) 2x +1, 2x +3ย  ย  (b) 3x -1, 2x +1ย  ย  (c) 2x -3,2x +5ย  ย  ย (d) 2x +3,2x -1

Ans.

4xยฒ + 4x – 3

=4xยฒ + 6x – 2x – 3

=2x( 2x + 3) -1(2x + 3)

=(2x + 3)(2x – 1)

You can compensate us by donating any amount of money for our survival

Our Paytm NO 9891436286

NCERT Solutions of class 9 scienceย 

Chapter 1-Matter in our surroundings Chapter 9- Force and laws of motion
Chapter 2-Is matter around us pure? Chapter 10- Gravitation
Chapter3- Atoms and Molecules Chapter 11- Work and Energy
Chapter 4-Structure of the Atom Chapter 12- Sound
Chapter 5-Fundamental unit of life Chapter 13-Why do we fall ill ?
Chapter 6- Tissues Chapter 14- Natural Resources
Chapter 7- Diversity in living organism Chapter 15-Improvement in food resources
Chapter 8- Motion Last years question papers & sample papers

CBSE Class 9-Question paper of science 2020 with solutions

CBSE Class 9-Sample paper of science

CBSE Class 9-Unsolved question paper of science 2019

NCERT Solutions of class 10 maths

Chapter 1-Real number Chapter 9-Some application of Trigonometry
Chapter 2-Polynomial Chapter 10-Circles
Chapter 3-Linear equations Chapter 11- Construction
Chapter 4- Quadratic equations Chapter 12-Area related to circle
Chapter 5-Arithmetic Progression Chapter 13-Surface areas and Volume
Chapter 6-Triangle Chapter 14-Statistics
Chapter 7- Co-ordinate geometry Chapter 15-Probability
Chapter 8-Trigonometry

CBSE Class 10-Question paper of maths 2021 with solutions

CBSE Class 10-Half yearly question paper of maths 2020 with solutions

CBSE Class 10 -Question paper of maths 2020 with solutions

CBSE Class 10-Question paper of maths 2019 with solutions

NCERT solutions of class 10 science

Chapter 1- Chemical reactions and equations Chapter 9- Heredity and Evolution
Chapter 2- Acid, Base and Salt Chapter 10- Light reflection and refraction
Chapter 3- Metals and Non-Metals Chapter 11- Human eye and colorful world
Chapter 4- Carbon and its Compounds Chapter 12- Electricity
Chapter 5-Periodic classification of elements Chapter 13-Magnetic effect of electric current
Chapter 6- Life Process Chapter 14-Sources of Energy
Chapter 7-Control and Coordination Chapter 15-Environment
Chapter 8- How do organisms reproduce? Chapter 16-Management of Natural Resources

Solutions of class 10 last years Science question papers

CBSE Class 10 – Question paper of science 2020 with solutions

CBSE class 10 -Latest sample paper of science

NCERT solutions of class 11 maths

Chapter 1-Sets Chapter 9-Sequences and Series
Chapter 2- Relations and functions Chapter 10- Straight Lines
Chapter 3- Trigonometry Chapter 11-Conic Sections
Chapter 4-Principle of mathematical induction Chapter 12-Introduction to three Dimensional Geometry
Chapter 5-Complex numbers Chapter 13- Limits and Derivatives
Chapter 6- Linear Inequalities Chapter 14-Mathematical Reasoning
Chapter 7- Permutations and Combinations Chapter 15- Statistics
Chapter 8- Binomial Theorem ย Chapter 16- Probability

CBSE Class 11-Question paper of maths 2015

CBSE Class 11 – Second unit test of maths 2021 with solutions

NCERT solutions of class 12 maths

Chapter 1-Relations and Functions Chapter 9-Differential Equations
Chapter 2-Inverse Trigonometric Functions Chapter 10-Vector Algebra
Chapter 3-Matrices Chapter 11 – Three Dimensional Geometry
Chapter 4-Determinants Chapter 12-Linear Programming
Chapter 5- Continuity and Differentiability Chapter 13-Probability
Chapter 6- Application of Derivation CBSE Class 12- Question paper of maths 2021 with solutions
Chapter 7- Integrals
Chapter 8-Application of Integrals

50 important science questions for cbse 10 class

Chemical properties of acid and base

Anatomy of human brain

Physics viva voce questions

Chemistry viva voce questions & answers

Chemistry practical based questions

Solutions of previous years science & maths question papers

Solutions of class 10 Science question paper 2019 CBSE

Solutions of class 10 CBSE maths question paper 2020

CBSE Class 10 science question paper 2020 SET -3 solutions

Download e-book of Science NCERT 634 questions with solutions for Polytechnic and NDA entrance exams

 

 

 

 

Scroll to Top