Future Study Point

# NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics has been brought to you by Future Study Point to help you in your homework, assignments, and forthcoming examination of class 10 CBSE board exam. NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics is one of the greatest input study materials through which you can clear your concepts on Statistics of 10 class CBSE. All questions are solved by an expert in maths by a step-by-step method.

## NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Click for online shopping

Future Study Point.Deal: Cloths, Laptops, Computers, Mobiles, Shoes etc

Q1.A survey was conducted by a group of students as a part of their environmental awareness programm in which they collected the following data regarding the number of plants in 20 houses in a locality . Find the mean number of plants per house.

Which method did you use for finding the mean , and why ?

Ans.

 No. of Plants Class Mark (xi) No. of Houses (fi ) fixi 0 – 2 2 – 4 4  – 6 6 –  8 8 – 10 10 – 12 12 – 14 1 3 5 7 9 11 13 1 2 1 5 6 2 3 ∑fi   = 20 1 6 5 35 54 22 39 ∑fixi= 162

We have

Hence mean number of the plants is 8.1

The direct method is proper to use here because the values of observations and their frequencies are small.

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q2.Consider the following distribution of daily wages of 50 workers of a factory. Find the mean daily wages of the workers of the factory by using an appropriate method.

Ans.

 Class Interval Class Mark (xi) Frequency(fi) ui=(xi-A)/h fixi 100 – 120 110 12 -2 -24 120 – 140 130 14 -1 -14 140 – 160 150 = A 8 0 0 160 – 180 170 6 1 6 180 – 200 190 10 2 20 ∑fi   = 50 ∑fiui= -12

Since the class interval is of the size,h= 20 and sum of frequencies is 50, both of them are large therefore applying the step deviation method

Hence the mean daily wages of the workers of the factory  is 145.20

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q3. The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.

Ans.

 Daily pocket allowance (in Rs) Class mark(xi) Frequency(fi) di=   xi-A fidi 11 – 13 13 – 15 15 – 17 17 – 19 19 – 21 21 – 23 23 – 25 12 14 16 18 = A 20 22 24 7 6 9 13 f 5 4 -6 -4 -2 0 2 4 6 -42 -24 -18 0 2f 20 24 ∑fi   = 44 + f ∑fidi= 2f – 40

Applying the shortcut method of mean

Where A = 18, ∑fidi= 2f – 40 , ∑fi   = 44 + f  and

2f – 40 = 0⇒ f = 20

Hence missing frequency is 20

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q4.Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.

Ans.

 No of heart beats per minute Class mark(xi) Frequency(fi) fixi 65 – 68 66.5 2 133 68 – 71 69.5 4 278 71 – 74 72.5 3 217.5 74 – 77 75.5 8 604 77 – 80 78.5 7 549.5 80 – 83 81.5 4 326 83 – 86 84.5 2 169 ∑fi= 30 ∑fixi= 2277

Applying the direct method for getting the mean of the data

Hence mean of the heartbeats per minute of the women is 75.9

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q5. In a retail market ,fruit vendors were selling mangoes kept in packing boxes.These boxes contained varying number of mangoes .The following was the distribution of mangoes according to the number of boxes.

Find the mean number of the mangoes kept in a packing box. Which method of finding the mean did you choose.

Ans.

 No of mangoes Class mark(xi) Frequency (fi) ui=(xi-A)/h fiui 50 – 52 53 – 55 56 – 58 59 – 61 62 – 64 51 54 57= A 60 63 15 110 135 115 25 -2 -1 0 1 2 -30 -110 0 115 50 ∑fi= 400 ∑fiui = 25

Here we have to apply step deviation because class intervals are not continuous

Hence the mean number of the mangoes kept in a packing box is 57.19

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q6.The table below shows the daily expenditure on food of 25 households in a locality.

Find the mean daily expenditure on food by suitable method.

Ans..

 Daily expenditure(in Rs) Class marks(xi) Frequency (fi) ui= (xi -A)/h fiui 100 – 150 125 4 -2 -8 150 – 200 175 5 -1 -5 200 – 250 225 12 0 0 250 – 300 275 2 1 2 300 – 350 325 2 2 4 ∑fi=25 ∑fiui= -7

Hence the mean daily expenditure on food is 211

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q7. To find out the concentration of SO2 in the air (in parts per million,i.e PPM) ,the data was collected for 30 localities in a certain city and is presented below.

Ans.

 Concentration of SO2(PPM) Class Mark(xi) Frequency(fi) ui=(xi -A)/h fixi o.oo – 0.04 0.02 4 -2 -8 0.04 – 0.08 0.06 9 -1 -9 0.08 – 0.12 0.10 9 0 0 0.12 – 0.16 0.14 2 1 2 0.16 – 0.20 0.18 4 2 8 0.20 – 0.24 0.22 2 ∑fi=30 3 6 ∑fiui=-1

Applying the step deviation method for getting the mean

Hence the average concentration of SO2 is 0.0987

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q8. A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.

Ans.

 No. of days Class Mark(xi) Frequency (fi) fixi 0 – 6 3 11 33 6 – 10 8 10 80 10 – 14 12 7 84 14 -20 17 4 68 20 – 28 24 4 96 28 – 38 33 3 99 38 – 40 39 1 39 ∑fi= 40 ∑fixi= 499

Applying direct method of getting the mean

=12 .48

The mean number of days a student was absent is 12.48

NCERT Solutions For Class 10 Maths Exercise 14.1 Statistics

Q9.The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate.

Ans.

 Litracy rate (%) Class mark(xi) Frequency(fi) ui= (xi– A)/h fixi 45 – 55 50 3 -2 -6 55 – 65 60 10 -1 -10 65 – 75 70 = A 11 0 0 75 – 85 80 8 1 8 85 – 95 90 3 ∑fi= 35 2 6 ∑fiui=-2

Applying the step deviation method

Where A = 70, h = 10

= 70 – 0.57 = 69.43 %

Hence the mean litracy rate is 69.43 %

You can compensate us by donating any amount of money for our survival

## NCERT Solutions of  Science and Maths for Class 9,10,11 and 12

### NCERT Solutions of class 9 maths

 Chapter 1- Number System Chapter 9-Areas of parallelogram and triangles Chapter 2-Polynomial Chapter 10-Circles Chapter 3- Coordinate Geometry Chapter 11-Construction Chapter 4- Linear equations in two variables Chapter 12-Heron’s Formula Chapter 5- Introduction to Euclid’s Geometry Chapter 13-Surface Areas and Volumes Chapter 6-Lines and Angles Chapter 14-Statistics Chapter 7-Triangles Chapter 15-Probability Chapter 8- Quadrilateral

### NCERT Solutions of class 9 science

CBSE Class 9-Question paper of science 2020 with solutions

CBSE Class 9-Sample paper of science

CBSE Class 9-Unsolved question paper of science 2019

### NCERT Solutions of class 10 maths

CBSE Class 10-Question paper of maths 2021 with solutions

CBSE Class 10-Half yearly question paper of maths 2020 with solutions

CBSE Class 10 -Question paper of maths 2020 with solutions

CBSE Class 10-Question paper of maths 2019 with solutions

### Solutions of class 10 last years Science question papers

CBSE Class 10 – Question paper of science 2020 with solutions

CBSE class 10 -Latest sample paper of science

### NCERT solutions of class 11 maths

 Chapter 1-Sets Chapter 9-Sequences and Series Chapter 2- Relations and functions Chapter 10- Straight Lines Chapter 3- Trigonometry Chapter 11-Conic Sections Chapter 4-Principle of mathematical induction Chapter 12-Introduction to three Dimensional Geometry Chapter 5-Complex numbers Chapter 13- Limits and Derivatives Chapter 6- Linear Inequalities Chapter 14-Mathematical Reasoning Chapter 7- Permutations and Combinations Chapter 15- Statistics Chapter 8- Binomial Theorem Chapter 16- Probability

CBSE Class 11-Question paper of maths 2015

CBSE Class 11 – Second unit test of maths 2021 with solutions

### NCERT solutions of class 12 maths

 Chapter 1-Relations and Functions Chapter 9-Differential Equations Chapter 2-Inverse Trigonometric Functions Chapter 10-Vector Algebra Chapter 3-Matrices Chapter 11 – Three Dimensional Geometry Chapter 4-Determinants Chapter 12-Linear Programming Chapter 5- Continuity and Differentiability Chapter 13-Probability Chapter 6- Application of Derivation CBSE Class 12- Question paper of maths 2021 with solutions Chapter 7- Integrals Chapter 8-Application of Integrals
Scroll to Top
Optimized by Seraphinite Accelerator
Turns on site high speed to be attractive for people and search engines.