Solutions for Class 12 Maths Exercise 5.3 of Chapter 5 Continuity and Differentiability
NCERT Solutions for Class 12 Maths Exercise 5.3 of Chapter 5 Continuity and Differentiability are available here for doing your homework , class assignments, and preparation of your forthcoming exams. NCERT solutions of maths are the best tools for achieving excellence in the maths subject.NCERT Solutions for Class 12 Maths Exercise 5.3 of Chapter 5 Continuity and Differentiability are created by an expert maths teacher who has experience of 25 years in teaching maths subjects.
NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability
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NCERT Solutions for Class 12 Maths Exercise 5.3 of Chapter 5 Continuity and Differentiability
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Find dy/dx in the following exercise 1 to 15.
Q1.2x + 3y = sinx
Ans.Differentiating the given function 2x + 3y = sinx with respect to x
Q2. 2x + 3y = siny
Ans.Differentiating the given function 2x + 3y = sinx with respect to x
Q3. ax + bx² = cosy
Ans. Given function is ax + bx² = cosy
Derivate function with respect to x , we have
Q4. xy + y² = tan x + y
Ans. Given function is xy + y² = tan x + y
Derivation function will respect to x, we have
Q5. x² + xy + y² = 100
Ans.The given function is x² + xy + y² = 100
Differentiating the given function with respect to x
Q6.x³ + x²y + y²x + y³ = 81
Ans.The given function is x³ + x²y + y²x + y³ = 81
Differentiating the given function with respect to x
Q7. sin²y + cosxy = π
Ans.The given function is sin²y + cosxy = π
Differentiating the given function with respect to x
Q8. sin²x + sin²y = 1
Ans.The given function is sin²x + sin²y = 1
Differentiating the given function with respect to x
Ans. The given function is
Simplifying the given function
Let x = tan θ
Putting back
Differentiating it with repect to x
Q10.
Ans. The given function is
First of all simplifying the function
Let x = tanθ
y = 3θ
Putting back θ = tan-1x
y = 3 tan-1x
Differentiating it with respect to x
The given function is
First of all simplifying the given function
Let x = tanθ
y =cos-1(cos2θ)
y = 2θ
Putting back θ =tan-1x
y = 2tan-1x
Differentiating it with respect to x
Ans. The given function is
First of all simplifying the given function
Let x = tanθ
y =sin-1(cos2θ)
y =sin-1sin(π/2-2θ)
y =π/2 -2θ
Putting back θ =tan-1x
y = π/2 -2tan-1x
Differentiating the function with respect to x
Ans. The given function is
First of all simplifying the given function
Let x = tanθ
y =cos-1(sin2θ)
y =cos-1cos(π/2-2θ)
y =π/2 -2θ
Putting back θ =tan-1x
y = π/2 -2tan-1x
Differentiating the function with respect to x
Ans.The given function is
First of all simplifying the given function
Let x =sinθ
y =sin-1(2sinθ.cosθ)
y =sin-1(sin2θ)
y = 2θ
Putting back θ =tan-1x
y = 2tan-1x
Differentiating the function with respect to x
Ans.The given function is
First of all simplifying the given function
Let x =cosθ
y =sec-1(sec2θ)
y = 2θ
Putting back θ =cos-1x
y = 2cos-1x
Differentiating the function with respect to x
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NCERT Solutions of Science and Maths for Class 9,10,11 and 12
NCERT Solutions of class 9 maths
Chapter 1- Number System | Chapter 9-Areas of parallelogram and triangles |
Chapter 2-Polynomial | Chapter 10-Circles |
Chapter 3- Coordinate Geometry | Chapter 11-Construction |
Chapter 4- Linear equations in two variables | Chapter 12-Heron’s Formula |
Chapter 5- Introduction to Euclid’s Geometry | Chapter 13-Surface Areas and Volumes |
Chapter 6-Lines and Angles | Chapter 14-Statistics |
Chapter 7-Triangles | Chapter 15-Probability |
Chapter 8- Quadrilateral |
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CBSE Class 10-Question paper of maths 2021 with solutions
CBSE Class 10-Half yearly question paper of maths 2020 with solutions
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NCERT solutions of class 11 maths
Chapter 1-Sets | Chapter 9-Sequences and Series |
Chapter 2- Relations and functions | Chapter 10- Straight Lines |
Chapter 3- Trigonometry | Chapter 11-Conic Sections |
Chapter 4-Principle of mathematical induction | Chapter 12-Introduction to three Dimensional Geometry |
Chapter 5-Complex numbers | Chapter 13- Limits and Derivatives |
Chapter 6- Linear Inequalities | Chapter 14-Mathematical Reasoning |
Chapter 7- Permutations and Combinations | Chapter 15- Statistics |
Chapter 8- Binomial Theorem | Chapter 16- Probability |
CBSE Class 11-Question paper of maths 2015
CBSE Class 11 – Second unit test of maths 2021 with solutions
NCERT solutions of class 12 maths
Chapter 1-Relations and Functions | Chapter 9-Differential Equations |
Chapter 2-Inverse Trigonometric Functions | Chapter 10-Vector Algebra |
Chapter 3-Matrices | Chapter 11 – Three Dimensional Geometry |
Chapter 4-Determinants | Chapter 12-Linear Programming |
Chapter 5- Continuity and Differentiability | Chapter 13-Probability |
Chapter 6- Application of Derivation | CBSE Class 12- Question paper of maths 2021 with solutions |
Chapter 7- Integrals | |
Chapter 8-Application of Integrals |