**NCERT Solutions for Class 12 Maths Exercise 5.6 of Chapter 5 Continuity and Differentiability**

NCERT Solutions for Class 12 Maths Exercise 5.6 of Chapter 5 Continuity and Differentiability will clear your doubts on the concept of Continuity and Differentiability that help you in preparing your worksheet, doing your homework, and class assignments of maths.NCERT Solutions for Class 12 Maths Exercise 5.6 of Chapter 5 Continuity and Differentiability are created by Future Study Point for boosting your preparation of the CBSE Board Maths question paper 2021-22.NCERT Solutions of Maths class 12 are the best study materials for clearing your concept on Continuity and Differentiability.

**NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability**

You can also study

**Continuity and Differentiability of a function**

**Exercise 5.1-Continuity and Differentiability**

**Exercise 5.2-Continuity and Differentiability**

**Exercise 5.3-Continuity and Differentiability**

**Exercise 5.4 – Continuity and Differentiability**

**Exercise 5.5-Continuity and Differentiability**

**Exercise 5.6-Continuity and Differentiability**

**NCERT Solutions for Class 12 Maths Exercise 5.6 of Chapter 5 Continuity and Differentiability**

**Click for online shopping**

**Future Study Point.Deal: Cloths, Laptops, Computers, Mobiles, Shoes etc**

If x and y are connected parametrical by the equations given in the exercise 1 to 10 ,without eliminating the parameter, find dy/dx.

Q1. x = 2at^{2}, y = at^{4}

Ans. The functions are x = 2at^{2}, y = at^{4}

Taking x = 2at^{2}

Differentiating the function with respect to t

Taking y = at^{4}

Differentiating the function with respect to t

Dividing equation (ii) by the equation (i)

**Q2.x = acosθ, y = bcosθ**

Ans. Taking x = acosθ

Differentiating the given function with respect to θ

Taking y = bcosθ

Differentiating the given function with respect to θ

Dividing equation (ii) by the equation (i)

**Q3. x = sin t, y = cos 2t**

Ans. Taking x = sin t

Differentiating the given function with respect to t

Taking y = cos 2t

Dividing equation (ii) by the equation (i)

Ans. Taking x = 4t

Taking

…….(ii)

Dividing equation (ii) by the equation (i)

**Q5. x = cos θ – cos 2θ, y =sin θ – sin 2θ**

Ans. The given functions are x = cos θ – cos 2θ, y =sin θ – sin 2θ

Taking x = cos θ – cos 2θ

Taking y =sin θ – sin 2θ

Dividing equation (ii) by the equation (i)

**Q6. x = a(θ – sin θ), y = a(1 + cos θ)**

Ans.The given functions are x = a(θ – sin θ), y = a(1 + cos θ)

Taking x = a(θ – sin θ)

Differentiating the function with respect to x

Taking y = a(1 + cos θ)

Differentiating the function with respect to x

Dividing equation (ii) by the equation (i)

Ans. The given functions are

Taking

Differentiating the function with respect to t

Taking

Differentiating the function with respect to t

Multiplying numerator and denominator by √(cos2t)

Dividing equation (ii) by the equation (i)

**Q8.x = a(cost + log tan t/2), y = a sin t**

Ans. The given functions are x = a(cost + log tan t/2), y = a sin t

Taking x = a(cost + log tan t/2)

Differentiating the function with respect to x

Taking **y = a sin t**

Differentiating the function with respect to t

Dividing equation (ii) by the equation (i)

**Q9. x = a sec θ, y = b tan θ**

Ans. The given functions are x = a sec θ, y = b tan θ

Taking x = a sec θ

Differentiating the function with respect to θ

Taking y = b tan θ

Differentiating the function with respect to θ

Dividing equation (ii) by the equation (i)

**Q10. x = a(cos θ + θ sin θ), y = a (sinθ – θ cos θ)**

Ans. Taking x = a(cos θ + θ sin θ)

Differentiating the function with respect to θ

Taking y = a (sinθ – θ cos θ)

Differentiating the function with respect to θ

Dividing equation (ii) by the equation (i)

**Show that dy/dx = -y/x**

Ans. Taking

Differentiating the function with respect to t

Taking

Differentiating the function similarly as above,we get

Dividing equation (ii) by the equation (i)

Substituting the values ,

, Hence proved

**You can com****pensate us by donating any amount of money for our survival**

**Our Paytm NO 9891436286**

**NCERT Solutions of Science and Maths for Class 9,10,11 and 12**

**NCERT Solutions of class 9 maths**

**NCERT Solutions of class 9 science **

**CBSE Class 9-Question paper of science 2020 with solutions**

**CBSE Class 9-Sample paper of science**

**CBSE Class 9-Unsolved question paper of science 2019**

**NCERT Solutions of class 10 maths**

**CBSE Class 10-Question paper of maths 2021 with solutions**

**CBSE Class 10-Half yearly question paper of maths 2020 with solutions**

**CBSE Class 10 -Question paper of maths 2020 with solutions**

**CBSE Class 10-Question paper of maths 2019 with solutions**

**NCERT solutions of class 10 science**

**Solutions of class 10 last years Science question papers**

**CBSE Class 10 – Question paper of science 2020 with solutions**

**CBSE class 10 -Latest sample paper of science**

**NCERT solutions of class 11 maths**

Chapter 1-Sets | Chapter 9-Sequences and Series |

Chapter 2- Relations and functions | Chapter 10- Straight Lines |

Chapter 3- Trigonometry | Chapter 11-Conic Sections |

Chapter 4-Principle of mathematical induction | Chapter 12-Introduction to three Dimensional Geometry |

Chapter 5-Complex numbers | Chapter 13- Limits and Derivatives |

Chapter 6- Linear Inequalities | Chapter 14-Mathematical Reasoning |

Chapter 7- Permutations and Combinations | Chapter 15- Statistics |

Chapter 8- Binomial Theorem | Chapter 16- Probability |

**CBSE Class 11-Question paper of maths 2015**

**CBSE Class 11 – Second unit test of maths 2021 with solutions**

**NCERT solutions of class 12 maths**

Chapter 1-Relations and Functions | Chapter 9-Differential Equations |

Chapter 2-Inverse Trigonometric Functions | Chapter 10-Vector Algebra |

Chapter 3-Matrices | Chapter 11 – Three Dimensional Geometry |

Chapter 4-Determinants | Chapter 12-Linear Programming |

Chapter 5- Continuity and Differentiability | Chapter 13-Probability |

Chapter 6- Application of Derivation | CBSE Class 12- Question paper of maths 2021 with solutions |

Chapter 7- Integrals | |

Chapter 8-Application of Integrals |