Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions is created for the class 10 Maths students who has chosen Maths -Basic, question paper of maths basic consists of 50 multiple questions. The students have to solve 40 questions. Each question carries 1 mark. The basic maths question paper with solutions is helpful for the students in their Term -1 exam CBSE Board 2021.The importance of studying these solutions of basic maths question paper preboard exam is to get the idea about the type of the questions in Term 1 CBSE Board exam 2021.
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Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
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Q1. After how many places of decimal will the decimal expansion of the number 27/(2ยฒร5ยณ) terminate ?
(a) 3ย ย ย ย ย ย (b) 4ย ย ย ย ย ย (c) 4ย ย ย ย ย ย (d) 1
Ans. (a) 3
(27)/(2ยฒร5ยณ)
Multiplying the denominator and numerator by 2
54/(2ร5)ยณ= 0.054
Q2. A die is thrown once. The probability of getting an even number is :
(a) 1/3ย ย ย ย ย ย (b) 1/6ย ย ย (c) 1/4ย ย ย ย ย ย (d) 1/2
Ans.(d) 1/2
When a die is thrown once,the total possible outcomes are = 6(1,2,3,4,5,6)
Favourable outcomes = 2,4 and 6
P(E) = favourable outcomes/total possible outcomes
P(even number) = 3/6 = 1/2
Q3. Sum of two numbers is 35 and their difference is 13,then the numbers areย
(a) 24,13ย ย ย ย (b) 24,11ย ย ย ย ย (c) 12,11ย ย ย ย ย ย (d) 12,23
Ansย (b) 24,11
(Let the numbers are x and y
x + y = 35…….(i)ย and x – y = 13……(ii)
Adding both equation
2x = 48 โx = 24
Putting the value in equation (i)
24 + y = 35
y = 11
Q4. The value of sin 60ยฐ/cos 30ยฐ is
(a) โ3/2ย ย ย ย ย ย (b) 1/2ย ย ย ย ย ย (c) 1ย ย ย ย ย ย (d) 2
Ans. (c) 1
Q5. If a bag contains 3 red and 7 black balls, then what will be the probability of getting a black ball ?
(a) 3/10ย ย ย ย ย (b) 4/10ย ย ย ย ย (c) 7/10ย ย ย ย ย (d) 5/10
Ans. (c) 7/10
Total number of balls are = 3 red balls + 7 black ball = 10 balls
The number of black balls = 7
P(black ball) = 7/10
Q6.The HCF of 5^{13} and 2^{6ย ย }will be
(a) 0ย ย ย ย (b) 1ย ย ย ย ย (c) 13ย ย ย ย (d) 26
Ans.(b) 1
The numbers givenย 5^{13} and 2^{6}are co-prime numbers(1 is a common factor between them)
- Q7. Equationsย a_{1}x + b_{1}y + c_{1}= 0 andย a_{2}x + b_{2}y + c_{2}= 0 has infinite many solutions if :
(a)ย a_{1}/ a_{2}โ b_{1}/ b_{2ย ย ย }(b) a_{1}/ a_{2}=b_{1}/ b_{2ย ย ย }(c) a_{1}/ a_{2}= b_{1}/ b_{2}=c_{1}/ c_{2ย ย ย }(d) a_{1}/ a_{2}= b_{1}/ b_{2}โ c_{1}/ c_{2}
_{Ans.ย ย }(c) a_{1}/ a_{2}= b_{1}/ b_{2}=c_{1}/ c_{2ย ย }
Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
Q8. sin 2A = 2 sin A is true when A is equal to
(a) 0ยฐย ย ย ย ย (b) 30ยฐย ย ย ย ย (c) 45ยฐย ย ย ย ย (d) 60ยฐ
Ans. (a) 0ยฐ
The value of LHS sin (2ร0ยฐ) =sin 0ยฐ = 0
The value of RHS 2 sin A = 2ร sin 0ยฐ = 2ร0 = 0
Hence,at A = 0,sin 2A = 2sin A
Q9. If the ratio of areas of two circle are 4 : 9, then the ratio of their radii will be:
(a) 4 : 9ย ย ย ย ย (b) 2 : 3ย ย ย ย ย (c) 8 : 27ย ย ย ย ย (d) 3 : 2
Ans. (b) 2 : 3
Area of the circle is = ฯrยฒ
Let the radii of two circles are r_{1 }and r_{2}
ฯr_{1}ยฒ/ฯr_{2}ยฒ = 4/9
r_{1}ยฒ/r_{2}ยฒ = 4/9
r_{1}/r_{2}ย = 2/3
Q10. Distance between the points (-1,3) and (2,-1) is
(a) 1 unitย ย ย ย (b) 6 unitsย ย ย ย (c) 5 unitsย ย ย ย (d) 7 units
Ans. (c) 5 units
The distance(d) between two points (x_{1},y_{1 }) and (x_{2},y_{2}) is
d= โ[(x_{2}-x_{1})ยฒ+ (y_{2}– y_{1})ยฒ]
The distance between (-1,3) and (2,-1) is
d = โ[(2+1)ยฒ+ (-1- 3)ยฒ] =โ[3ยฒ +(-4)ยฒ] =โ(9 +16) =โ25 = 5 units
Q11. How many rational numbers are there between any two rational numbers ?
(a) 1ย ย ย ย ย (b) 2ย ย ย ย ย ย ย (c) 3ย ย ย ย ย ย (d) infiitely many
Ans. (d) infinitely many
There are numberless numbers and any sets of numbers are infinite, hence between two rational numbers, there are infinite numbers.
Q12. If coordinates of the diameter of a circle are (-6,3) and (6,9), then the coordinates of the centre is:
(a) (8,-8)ย ย ย ย (b) (12,6)ย ย ย ย (c) (0,6)ย ย ย ย (d) (0,3)
Ans. (c) (0,6)
The mid point between ย two points (x_{1},y_{1 }) and (x_{2},y_{2}) is =ย (x_{1}+x_{2 })/2,ย (y_{1}+y_{2})/2
The midpoints of the diameter is the centre of the circle
The endpoints of the diameter are (-6,3) and (6,9)
The coordinates of the centre of the circle are = (-6+6)/2,( 3+9)/2 = (0,6)
Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
Q13.If quadratic polynomial p(x) = xยฒ – x + 4 has roots ฮฑ and ฮฒ, then the value of ฮฑ + ฮฒ is :
(a) -1ย ย ย ย ย (b) 1ย ย ย ย ย ย (c) 4ย ย ย ย ย ย (d) 0
Ans. (b) 1
In the standard quadratic equation axยฒ + bx + c, if the roots areย ย ฮฑ and ฮฒ
ฮฑ + ฮฒ = -b/a
The given quadratic polynomial is
p(x) = xยฒ – x + 4 ,where a = 1 and b = -1
ฮฑย + ฮฒ = -(-1)/1 = 1
Q14. ย is a /an
(a) Integerย ย ย ย ย (b) Rational Numberย ย ย (c) Irrational Numberย ย (d) Natural Number
Ans.(b) Rational Number
= 2.353535……, which is a recurrent (repeating) infinite decimal numbers,it can be written in the form of P/Q,where P and Q are co-prime numbers
x = 2.353535…..(i)
Multiplying it by 100,we get equation (ii)
100 x = 235.3535….(ii)
Subtracting equation (i) from (ii)
99x = 233
x = 233/99
Q15. If tan (3x -15ยฐ) = 1,then the value of x is:
Ans.
tan (3x -15ยฐ) = 1
tan (3x -15ยฐ) = tan 45ยฐ
3x – 15ยฐ = 45ยฐ
3x = 60ยฐ
x = 20ยฐ
Q16.From a well shuffled cards,the probability of getting a red face card is:
(a) 3/26ย ย ย (b) 6/13ย ย ย ย (c) 3/52ย ย ย ย (d) 1/13
Ans. Total number of cards are = 52
The number of red face cards are = 26
P( getting a red face card) = (number of red face cards)/(total number of cards) = 26/52 =1/2
Q17. In what ratio the point P(0,0) divides the line segment joining the points A(3,3) and B(-3,-3)?
(a) 1 : 2ย ย ย ย (b) 1 : 3ย ย ย ย (c) 1 : 4ย ย ย ย ย (d) 1 : 1
Ans.ย (d) 1 : 1
Applying the section formula
x = (mx_{2}+nx_{1})(m+n), y ย = (my_{2}+ny_{1})(m+n)
We are given that the point P(0,0)ย divides the line segment A(3,3)ย and B(-3,-3)
0 = (mร-3 +nร3)/(m+n)
-3m + 3n = 0
-3m = -3n
m : n = 1 : 1
Q18. The pair of linear equation 6x – 7y = 1 and 3x – 4y = 5 has solution:
(a) Two solutionsย ย ย ย (b) Infinitely many solutionsย ย (c) Unique solutionย (d) No solution
Ans. (c) Uniques solution
From the given equation 6x -7y =1 and 3x -4y =5,we have the coefficients
are a_{1}=6,b_{1}=-7, c_{1}=-1,a_{2}=3,b_{2}=-4,c_{2}= -5
a_{1}/ a_{2}= 6/3 = 2, b_{1}/ b_{2}=(-7)/(-4) = 7/4, c_{1}/c_{2}= (-1)/(-5) = 1/5
a_{1}/ a_{2}โ b_{1}/ b_{2}
Therefore both equations has a uniques solution
Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
Q19.If the distance between the points A (4,P) and B(1,0) is 5 units, then the value of P are :
(a) 4,0ย ย ย ย ย (b) -4,0ย ย ย ย (c) 4, -4ย ย ย ย ย (d) 0, 1
Ans. (c) 4, -4
The distance(d) between two points (x_{1},y_{1 }) and (x_{2},y_{2}) is
d= [(x_{2}-x_{1})ยฒ+ โ(y_{2}– y_{1}])ยฒ
The distance between the points A (4,P) and B(1,0) is 5 units
5 = ย [(1-4)ยฒ+ โ(0- P])ยฒ
25 = (-3)ยฒ + (-P)ยฒ
Pยฒ = 25 -9 = 16
P = ยฑ 4
Q20. 225 can be expressed as :
(a) 5ยฒ ร 3ยฒย ย ย ย ย (b) 5ยฒร 3ย ย ย ย (c) 5ยฒร 3ยฒย ย ย (d) 5ยณร 3
Ans. 5ยฒร3ยฒ
225 = 3ร3ร5ร5 = 5ยฒร 3ยฒ
Q21. In an isosceles triangle ABC, if AC = BC and ABยฒ = 2ACยฒ, then value of C is:
(a) 30ยฐย ย ย ย ย ย ย ย ย ย (b) 45ยฐย ย ย ย ย ย ย ย (c) 60ยฐย ย ย ย ย ย (d) 90ยฐ
Ans.
The given triangle is isosceles triangle in which AC = BC and we are given ABยฒ = 2ACยฒ
ABยฒ = 2ACยฒ = ACยฒ + ACยฒ
Putting AC = BC
ABยฒ = BCยฒ + ACยฒ
AB =Hyptenuse ,BC and AC are perpendicular to each other
โด โ C = 90ยฐ
Q22. In a triangle ABC ,DE parallel to BC, then the value of EC is
(a) 5 cmย ย ย (b) 10 cmย ย ย ย (c) 8 cmย ย ย ย (d) 10 cm
Ans.(c) 8 cm
In ฮABC and ฮADE
DE parallel to BC and AB is the transversal
โ ADE = โ ABC (corresponding angle)
โ AED = โ ACB (corresponding angle)
โดฮABC โผฮADE (AA rule criteria)
Applying the rule of similar triangles
AD/AB = AE/AC = DE/BC
3/(3 +4) = 6/AC
3/7 = 6/AC
3AC = 42
AC = 14
EC = AC – AE = 14 – 6 = 8 cm
Q23. The parimeter of semicircular protector whose radius โr โ is
(a) ฯ + rย ย ย ย ย (b) ฯrย ย ย ย ย (c) ฯ + 2rย ย ย ย (d) ฯr + 2r
Ans. The perimeter of semicircular protector = Length of the semicircular arc + Diameter
Length of semicircular arc = (2ฯr)/2 =ฯr
Diameter = 2r
Hence perimeter of semicircular protector = ฯr + 2r
Q24. What is the area of a sector of a circle with radius 14 cm and central angle 45ยฐ?
(a)76 cmยฒย (b) 77 cmยฒย ย ย (c)66 cmยฒย ย ย (d) 55 cmยฒ
Ans. (b) 77 cmยฒ
Area of sector of a circle is given as
Where ฮธ = 45ยฐ, r = 14 cm
Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
Q25. What will be radius of the circle whose circumference is 44 m ?
(a) 14 mย ย ย ย (b) 7 mย ย ย ย (c) 5 mย ย ย ย (d) 44 m
Ans.(b) 7 m
The circumerence of the circle =2ฯr
The circumference of the given circle is = 44 m
2ฯr = 44
2 (22/7) r = 44
r = (44ร7)/(44) = 7 m
Q26. (1 +tanยฒA)/cosecยฒA will be equal to:
(a) secยฒAย ย ย ย ย ย ย ย (b) cosecยฒAย ย ย ย ย (c) cotยฒAย ย ย ย ย (d) tanยฒA
Ans. (d) tanยฒA
The given expression is
(1 +tanยฒA)/cosecยฒA
Converting tan A and cosec A into sin A and cos A
(1 + sinยฒA/cosยฒA)
Q27. If p and q are co-prime numbers, then the HCF of pยณqยฒ and pยฒq will be:
(a) pยณqยฒย ย ย ย (b) pยฒqย ย ย ย ย (c) pยฒqยฒย ย ย (d) pq
Ans. (b) pยฒq
Since p and q are co-prime numbers,therefore in p and q there is no common factor except to 1.
The HCF ofย pยณqยฒย and pยฒq is = the lower power of p in both terms ร lower power of q in both terms =pยฒq
Q28. In equation x + 2y =9 ,if x = 5,then the value of y will be:
(a) 1ย ย ย ย ย (b) -2ย ย ย ย (c) 2ย ย ย ย ย ย (d) 4
Ans. (c) 2
Putting x = 5 in given equation x + 2y =9
5 + 2y =9
2y = 9 -5 = 4
y = 4/2 = 2
Q29. If (2K -1,K) is the solution of 10 x -9y =12, then the value of K will be:
(a) 1ย ย ย ย ย ย (b) 2ย ย ย ย ย ย (c) 3ย ย ย ย ย (d) 4
Ans. (b) 2
The solution of the given equation is 10x – 9y =12 is =(2K-1,K)
Therefore putting x = 2K-1 and y = k in the given equation
10(2K-1) – 9K =12
20 K -10 -9K = 12
11K = 10 + 12 = 22
K = 2
Q30. If x = a cosฮธ and y = b sinฮธ, then the value of bยฒxยฒ +aยฒyยฒ is :
(a) aยฒ +bยฒย ย ย ย (b) aยฒ/bยฒย ย ย ย ย (c) aยฒbยฒย ย ย ย ย (d) 1/aยฒ + 1/bยฒ
Ans. (c) aยฒbยฒ
Putting the value of x = a cos ฮธ and y = b sin ฮธ in the expression bยฒxยฒ + aยฒyยฒ
bยฒ aยฒ cosยฒฮธ + aยฒbยฒ sinยฒฮธ
aยฒbยฒ( cosยฒฮธ + sinยฒฮธ) = aยฒbยฒ
Q31. Distance of the point Q(3,-4) from the origin is :
(a)ย 3 unitsย ย ย ย ย ย ย (b) 4 unitsย ย ย ย (c) 5 unitsย ย ย ย ย (d) 7 units
Ans. (c) 5 units
The coordinates of the origins are (0,0) and the point given to us is Q(3, -4),distance(d) between two two points is given as
d=โ [(x_{2}-x_{1})ยฒ+ โ(y_{2}– y_{1}])ยฒ
= โ[(3 -0)ยฒ + (-4 -0)ยฒ] = โ(3ยฒ + 4ยฒ) = โ(9 + 16) = โ25 = 5 units
Q32. If the point C(K,4) divides the line segement joining the two points A(2,6) and B(5,1) in the ratio 2 : 3, then the value of K is:
(a) 4/5ย ย ย ย (b) 16/5ย ย ย ย (c) 11/5ย ย ย ย ย (d) 19/5
Ans.(b) 16/5
Applying the section formula
x = (mx_{2}+nx_{1})(m+n), y ย = (my_{2}+ny_{1})(m+n)
Putting the value , x = K , y = 4, x_{1}
=2,x_{2 }= 5,ย y_{1}= 6,y_{2}=1, m : n = 2: 3
K=(2ร5 + 3ร2)/(2+3) =(10 +6)/5 = 16 /5
Q33. An event A is very unlikely to happen ,then its probabilty will be closest to :
(a) 0.0001ย ย ย ย ย (b) 0.001ย ย ย ย ย ย ย (c) 0.01ย ย ย ย (d) 0.1
Ans.
The probabilty of an event is very likely to happen =ย ย P(A)ย = 1
The sum of probabilty of an event andย not happening of the probabiltyย is equal to 1
Q34.In a linear equation ax +by +c = 0,a,b and c are:
(a) Natural numberย ย ย ย ย ย ย (b) Whole numberย ย ย ย (c) Integersย ย ย ย (d) Real Number
Ans. (d) Real Number
As an example โ2 x + 3y -4 = 0 ,3x + 3y – 5 = 0 ,both are linear equations,no matters if a,b and c are natural numbers,whole numbers,integers ,rational or irrational numbers ,so a,b and c should be real numbers.
Q35. If a pair of dice is thrown once,then probability of getting a sum of 8 will be :
(a) 1/6ย ย ย ย ย (b) 5/36ย ย ย ย (c) 1/9ย ย ย ย ย (d) 1/12
Ans. (b) 5/36
If a pair of dice is thrown once then the total outcomes are = 6ยฒ = 36
Theย outcomes in which sum of the digits in both dice is 8 are = (2,6),(3,5),(4,4),(5,3),(6,2) [i.e 5)
P(getting the sum of 8) = 5/36
Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
Q36.The perimeter of rectangle is 44 cm.Its length exceeds twice its breadth by 4 cm. Find the area of rectangle:
(a) 46 cmยฒย ย ย (b) 49 cmยฒย ย ย ย (c) 96 cmยฒย ย ย ย (d) 69 cmยฒ
Ans. (c) 96 cmยฒ
Let the breadth of rectangle = x cmย then length = (2x + 4 ) cm
Perimeter of the rectangleย given to us = 44 cm
Perimeter of the rectangle is = 2 ( L+ B) = 2( 2x + 4+x) = 2(3x + 4)
According to question
2(3x + 4) = 44
3x + 4 = 22
3x = 22 – 4 = 18
x = 6
Therefore breadth =6 cm and the length of rectangleย = 2x + 4 = 2ร6 + 4 =16 cm
Area of the rectangle = L ร B = 16 ร6 = 96 cmยฒ
Q37. If sin ฮธ = cos ฮธ, then the value of tan ยฒฮธ + cotยฒฮธ is:
(a) 2ย ย ย ย ย ย ย (b) 4ย ย ย ย ย ย (c) 1ย ย ย ย ย ย ย (d) 10/3
Ans. We are given
sin ฮธ = cos ฮธ
sinฮธ/cos ฮธ = 1
tan ฮธ = 1 โ cot ฮธ = 1/tan ฮธ = 1
The value of
tanยฒฮธ + cotยฒฮธ = 1ยฒ + 1ยฒ = 1 + 1 = 2
Te questions 38 -40 consists of Assertion (A) and Reason (R) . Answer these questions selecting the appropriate option given below:
(a) Both A and R are true and R is the correct exolanation of A.
(b) Both A and R are true but R is not the correct exolanation of A.
(c) A is true,but R is false
(d) A is false, but R is true
Q38.Assertion(A): The point (0,4) lies on the y-axis.
Reason(R): The x coordinate of the point on the y-axis is zero.
Ans.(a) Both A and R are true and R is the correct explanation of A.
The point (0,4) lies on the y -axis because x = 0
Class 10 Maths(Basic) Preboard Exam (First) 2021-22 CBSE with Solutions
Q39. Assertion(A): If the circumference of two circles are in the ratio 2 : 3, then the ratio of their areas is 4 : 9.
Reason(R): The circumference of a circle of radius is 2ฯr and its area is ฯrยฒ
Ans.(a) Both A and R are true and R is the correct explanation of A.
Let the radii of two circles are r_{1 }and r_{2}
The ratio of their circumference is given as 2 : 3
2ฯr_{1}/2ฯr_{2}= 2/3
r_{1}/r_{2}= 2/3
Ratio between their areas
= ฯr_{1}ยฒ/ฯr_{2}ยฒ = (r_{1}/r_{2})ยฒ =(2/3)ยฒ = 4/9
Q40. Assertion(A):ย For any two positive integers a and b, LCM (a,b) รHCF(a,b) = aร b.
Reason (R) : Product of two numbers is 150 and HCF is 5,then their LCM is 40.
Ans.(a) A is true but R is false
The relationship between HCF(a,b) and LCM(a,b) and the product of numbers a and bย is given as
LCM (a,b) รHCF(a,b) = ab
LCMร5 = 150
LCM = 150/5 =30
SECTION – C
(Case Study Basedย Questions)
Section โCโ consists of 10 questions. Do any 8 questions.
Points A and B are on the opposite edges of a pond a shown in below figure. To find distance between the two points, Ramesh makes a right angled triangle using the rope. Distance between point B and C is 12 m, distance betweenย C and D is 40 m andย A and D is 30 m such that โ ADC = 90ยฐ.
Q41. Which property of geometry is used to find the distance in the figure ?
(a) Similarity of trianglesย ย ย ย ย ย (b) Thales theorem
(c) Pythogorus theoremย ย ย ย ย ย ย ย ย ย ย ย (d) Converse of thales
Ans.Pythogorus theorem
Q42. What is total length of pond AB and rope BC in the figure ?
(a) 50 mย ย ย ย (b) 70 mย ย ย ย (c) 100 mย ย ย ย (d) 38 m
Ans. (a) 50 m
โ ADC = 90ยฐ
ADย and DC are perpendicular to each other
ACยฒ = ADยฒ + DCยฒ
ACยฒ = 30ยฒ + 40ยฒ = 900 + 1600 = 2500
AC = โ(2500) = 50
AB = AC – BC = 50 – 12 = 38
Q43. Length of the total rope used is:
(a) 82 mย ย ย ย (b) 70 mย ย ย ย (c) 120 mย ย ย ย (d) 100 m
Ans.(a) 82 m
The lenghth of total rope = BCย +DC + AD =12 + 40 + 30 = 82 m
Q44. Which of the following doesn’t form Pythagoras triplet ?
(a) (20,21,28)ย ย ย (b) (8,15,17)ย ย ย ย (c) (5,12,13)ย ย ย (d) (7,24,25)
Ans.(a) (20,21,28)
(a) 28ยฒ = 21ยฒ +20ยฒ
784 โ 441 + 400=841
(b) 17ยฒ = 15ยฒ + 8ยฒ
289 = 225 + 64 =289
(c) 13ยฒ = 12ยฒ + 5ยฒ
169 = 144 + 25 =169
(d)ย 25ยฒ = 24ยฒ + 7ยฒ
625 = 576 +49 = 625
(a) doesn’t show Pythogoras triplet because 28ยฒ โ 21ยฒ+20ยฒ
Q45. Length of the Pond AB is:
(a) 50 mย ย ย ย ย (b) 62 mย ย ย ย (c) 70 mย ย ย ย (d) 38 m
(d) 38 m
Case Study -II
The path moved by a group of ants has been traced on graph. Aditi is a student of class 10. She compared the ant’s path with the diagram she learned in maths class then she drew the sketch on the graph.
Q46. The shape of the path formed by ants is:
(a) Spiralย ย ย ย (b) Ovalย ย ย ย (c) Parabolaย ย ย (d) Linear
Ans. (c) Parabola
Q47. How many zeroes are possible for this shape ?
(a) 2ย ย ย ย ย (b) 3ย ย ย ย (c) 4ย ย ย ย (d) 0
Ans. (a) 2
A parabola can intersects any of the axises in two points,so maximum possible zeroes of the parabolic polynomial is 2.
Q48. According to graph ,the zeroes of the polynomial are:
(a) -3,-1ย ย ย ย (b) 3,-1ย ย ย ย (c) -3, 1ย ย ย ย ย (d) 0,0
Ans.(c) -3,1
The parabola is intersecting the x-axis at x = -3 and at x = 1,therefore its zeroes are -3,1
Q49. What will be the expression of the polynomial shown in figure?
(a) xยฒ -2x +3ย ย (b) xยฒ -3x +2ย ย (c) xยฒ +3x +2ย ย ย (d) xยฒ +2x – 3
Ans. (d) xยฒ +2x -3
The algebraic expression of a quadratic polynomial with zeroes ฮฑ and ฮฒ is given as
xยฒ – (ฮฑ +ฮฒ) x + ฮฑฮฒ
Here ฮฑ = -3 and ฮฒ = 1
xยฒ -(-3 +1)x +(-3) 1
xยฒ +2x -3
Q50. What will be the value of the polynomial if x = -1 ?
(a) -5ย ย ย ย ย (b) 6ย ย ย ย ย (c) -4ย ย ย ย (d) 0
Ans.(c) -4
The polynomial,P(x) = xยฒ +2x -3
P(-1)ย = (-1)ยฒ + 2(-1) -3 = 1 -2 -3 = 1-5 = -4
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Chapter 1- Number System | Chapter 9-Areas of parallelogram and triangles |
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Chapter 4- Linear equations in two variables | Chapter 12-Heron’s Formula |
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Chapter 1-Sets | Chapter 9-Sequences and Series |
Chapter 2- Relations and functions | Chapter 10- Straight Lines |
Chapter 3- Trigonometry | Chapter 11-Conic Sections |
Chapter 4-Principle of mathematical induction | Chapter 12-Introduction to three Dimensional Geometry |
Chapter 5-Complex numbers | Chapter 13- Limits and Derivatives |
Chapter 6- Linear Inequalities | Chapter 14-Mathematical Reasoning |
Chapter 7- Permutations and Combinations | Chapter 15- Statistics |
Chapter 8- Binomial Theorem | ย Chapter 16- Probability |
CBSE Class 11-Question paper of maths 2015
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Chapter 1-Relations and Functions | Chapter 9-Differential Equations |
Chapter 2-Inverse Trigonometric Functions | Chapter 10-Vector Algebra |
Chapter 3-Matrices | Chapter 11 – Three Dimensional Geometry |
Chapter 4-Determinants | Chapter 12-Linear Programming |
Chapter 5- Continuity and Differentiability | Chapter 13-Probability |
Chapter 6- Application of Derivation | CBSE Class 12- Question paper of maths 2021 with solutions |
Chapter 7- Integrals | |
Chapter 8-Application of Integrals |