Most Important Maths Questions of 3 and 4 marks for Class 10 CBSE-Part 1 - Future Study Point

Most Important Maths Questions of 3 and 4 marks for Class 10 CBSE-Part 1

most imp.maths questions

Most Important Maths Questions of 3 and 4 marks for Class 10 CBSE-Part 1

Most Important Maths Questions of 3 and 4 marks for Class 10 CBSE-Part 1 are created here, after examining the last year’s maths question papers of class 10 CBSE Board. The reason of selecting of 3 and 4 marks maths questions from last year’s question papers is based on the fact that these maths questions of 3 and 4 marks represent 65-70 % of the total marks of the maths question paper, therefore for achieving maximum percentage in maths every student needs special attention to 3 and 4 marks question since the practice of these maths questions leads the complete preparation of maths.

most imp.maths questions

 

Here, CBSE class 10 maths most important questions and answers for the 2019-20 board part I published by Future Study Point are presented for the students of 10 th class who are going to appear in the 2022-23 board exam of CBSE.

All the questions in CBSE class 10 maths most important questions and answers for 2022-23 board-Part 1 are designed by the expert of the subject and their answers are readily explained in an ordered way.

These  CBSE class 10 maths most important questions and answers for 2022-23 board-Part 1 are designed as per the updated syllabus of CBSE, so you need not to have any kinds of doubt in the selections of the questions. Don’t forget to make a comment and to subscribe us.

Why do you need to study 3 and 4 marks questions of maths

  • These maths questions represent 65-70% of total marks
  • The preparation of these maths questions also handles the preparation of other questions
  • Helpful in increasing the marks in maths
  • Increases the maths skill of the students

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Solutions of the Most important maths questions for Class 10 CBSE for Term-1 and Term 2

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CBSE Class 10-Half yearly question paper of maths 2020 with solutions

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Most Important Maths Questions of 3 and 4 marks for Class 10 CBSE-Part 1

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Q1. Prove that n³ – n is divisible by 6, where n is a positive integer.

Ans. n is given to us  a positive  integer

n³–n = n(n² – 1)= (n –1)n(n +1)

A number   divisible by 2 and 3 both then it  will be divisible by 6

So let us show (n –1)n(n +1) is divisible by 3 as well as by 2

Let it is divisible by 3, according to Euclid’s theorem the given expression can be written in the form of 3q + r ,then possible remainders will be 0, 1,2 and corresponding integers will be 3q, 3q +1, 3q +2

When n = 3q

(n–1)n(n +1) =(3q–1)3q(3q +1)

When n= 3q +1

(n–1)n(n +1) = (3q +1 –1)(3q +1)(3q + 1 +1)= 3q(3q+1)(3q +2)

When n = 3q + 2

(n–1)n(n +1) = (3q + 2 –1)(3q +2)(3q +2 +1)= (3q +1)(3q +2)(3q +3)=3(q +1)(3q +1)(3q +2)

In every case the given expression is divisible by 3

Now let the given expression is divisible by 2

Then according to Euclid’s theorem the given expression can be written as 2q+r where possible value of r = 0,1. So corresponding value of the expression will be 2q, 2q +1

(n–1)n(n +1) = (2q–1) 2q (2q +1)

(n–1)n(n +1)=(2q +1 –1) (2q +1) (2q +1 +1) =2q(2q +1)(2q + 2)

In evry case the expression is divisible by 2

We have proved that given number is divisible by 2 as well by 3, so it will also be divisible by 2 ×3=6.

Hence proved

Q2. The houses in a row are numbered consecutively from 1 to 49. Show that there exists a value of x such that sum of the number of houses preceding the house numbered x is equal to the sum of the number of houses following x.

Ans. The houses are numbered as follows,together we are also given a house number x within 1 to 49.

1,2,3,4…….x–1,x,x +1,x+2………..47,48,49

We are given the sum of house numbers preceding the house numbered x = Sum of  the house numbers followed by x

The houses from 1  to x – 1 will be as given bellow

Let S  is the sum of the numbers of houses preceding the house no.x and S’ is the sum of the numbers of houses followed by x

a =1, d =1, l =x –1

And

According to question

(x –1)x  = (49 – x)(x + 50)

x² –x = 49x +2450 –x² –50x

2x² = 245o

x ² =1225

x = √(1225)

x = 35

Therefore,the house no x = 35 exist as described in the question.

Q3.The first and the last terms of an AP are 10 and 361 respectively. If its common difference is 9 then find the number of terms and their total sum?

Ans. Let the total terms of the given AP in the question =n

a = 10, a= 361

d = 9

a= a + (n -1)d

361 = 10 + (n – 1) 9

9n – 9 +10 = 361

9n = 360

n = 40

Placing the value of n = 40 in the following formula

S40 = 20 × 371 = 7420

Therefore the number of terms in AP is 40 and sum of the terms of AP is 7420

Most Important Maths Questions of 3 and 4 marks for Class 10 CBSE-I

Q4. A motorboat whose speed is 24 km/hr in still water takes 1 hr more to go 32km  upstream than to return downstream to the same spot. Find the speed of the stream.

Ans. Let the speed of stream = x km/hr

Speed of motorboat in still water= 24 km/hr

Distance covered by the motorboat to go upstream = 32 km

The speed of the boat to go upstream = 24–x 

Speed of boat towards downstraem= 24+x

Let time taken by motorboat to go upstream = tand down stream = t2

Time = Distance/Time taken

Therefore

According to the question

t=  t+ 1

64x = 576 –x² 

x² + 64x –576 = 0

x² + 72x – 8x – 576 = 0

x(x + 72) – 8(x + 72) = 0

(x + 72)( x – 8) =0

x = –72, x = 8

The speed of  stream can not be negative,so avoiding –72

Therefore the speed of stream will be 8 km/hr 

Q5.A train was to cover a distance of 2800km in prefixed time duration. But due to the foggy weather, the speed of the train was slowed down which reduced the average speed of the train for the overall journey by 100 km/hr.  The time duration for the journey also increased by 30 min. Determine the original speed and travel time taken by the train.

Ans. Let the original speed of the train = x km/hr

The modified speed of the train due to fog = (x – 100 ) km/hr

Distance covered by the train = 2800 km

Let time taken  by original speed is tand by new speed  is t2

According to question  time taken by new speed = 30 min + time taken by original speed

30 min = 30/60 = 1/2 hr

x² – 100x – 560000 =0

x² – 800x + 700x –560000 =0

x(x – 800) + 700(x – 800) =0

(x – 800)(x + 700) =0

x = 800, x = –700

The original speed of the train is 800 km/hr.

And travel time is taken by the train= 2800/800= 28/8= 3.5 hr

Q6.If pth,qth and rth terms of an AP are x, y and z consecutively prove that

x(q –r) + y(r – p) + z(p – q) = 0

Answer.

As we know the n term of an AP = a + (n –1)d

x = a + (p – 1)d…….(1)

y = a + (q – 1)d……..(2)

z = a + (r – 1)d………(3)

Substituting the value of x, y, and z in RHS of the equation

[ a + (p – 1)d](q – r) + [a + (q – 1)d](r –p) +[a + (r – 1)d](p –q)

=a(q – r)  + (p – 1)(q – r) d + a(r –p) + (q – 1)(r –p)d +a(p –q)+ (r – 1)(p –q)d

=a(q – r  + r –p + p –q ) + d(pq –pr –q +r + qr –pq –r +p +pr –qr –p +q)

= a.0 + d.0 = 0 = R.H.S

See Solutions of more important questions for Class 10 CBSE in our Utube channel

NCERT Solutions of Science and Maths for Class 9,10,11 and 12

NCERT Solutions for class 9 maths

Chapter 1- Number System Chapter 9-Areas of parallelogram and triangles
Chapter 2-Polynomial Chapter 10-Circles
Chapter 3- Coordinate Geometry Chapter 11-Construction
Chapter 4- Linear equations in two variables Chapter 12-Heron’s Formula
Chapter 5- Introduction to Euclid’s Geometry Chapter 13-Surface Areas and Volumes
Chapter 6-Lines and Angles Chapter 14-Statistics
Chapter 7-Triangles Chapter 15-Probability
Chapter 8- Quadrilateral

NCERT Solutions for class 9 science 

Chapter 1-Matter in our surroundings Chapter 9- Force and laws of motion
Chapter 2-Is matter around us pure? Chapter 10- Gravitation
Chapter3- Atoms and Molecules Chapter 11- Work and Energy
Chapter 4-Structure of the Atom Chapter 12- Sound
Chapter 5-Fundamental unit of life Chapter 13-Why do we fall ill ?
Chapter 6- Tissues Chapter 14- Natural Resources
Chapter 7- Diversity in living organism Chapter 15-Improvement in food resources
Chapter 8- Motion Last years question papers & sample papers

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Chapter 1-Real number Chapter 9-Some application of Trigonometry
Chapter 2-Polynomial Chapter 10-Circles
Chapter 3-Linear equations Chapter 11- Construction
Chapter 4- Quadratic equations Chapter 12-Area related to circle
Chapter 5-Arithmetic Progression Chapter 13-Surface areas and Volume
Chapter 6-Triangle Chapter 14-Statistics
Chapter 7- Co-ordinate geometry Chapter 15-Probability
Chapter 8-Trigonometry

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Chapter 1- Chemical reactions and equations Chapter 9- Heredity and Evolution
Chapter 2- Acid, Base and Salt Chapter 10- Light reflection and refraction
Chapter 3- Metals and Non-Metals Chapter 11- Human eye and colorful world
Chapter 4- Carbon and its Compounds Chapter 12- Electricity
Chapter 5-Periodic classification of elements Chapter 13-Magnetic effect of electric current
Chapter 6- Life Process Chapter 14-Sources of Energy
Chapter 7-Control and Coordination Chapter 15-Environment
Chapter 8- How do organisms reproduce? Chapter 16-Management of Natural Resources

NCERT Solutions for class 11 maths

Chapter 1-Sets Chapter 9-Sequences and Series
Chapter 2- Relations and functions Chapter 10- Straight Lines
Chapter 3- Trigonometry Chapter 11-Conic Sections
Chapter 4-Principle of mathematical induction Chapter 12-Introduction to three Dimensional Geometry
Chapter 5-Complex numbers Chapter 13- Limits and Derivatives
Chapter 6- Linear Inequalities Chapter 14-Mathematical Reasoning
Chapter 7- Permutations and Combinations Chapter 15- Statistics
Chapter 8- Binomial Theorem  Chapter 16- Probability

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NCERT solutions for class 12 maths

Chapter 1-Relations and Functions Chapter 9-Differential Equations
Chapter 2-Inverse Trigonometric Functions Chapter 10-Vector Algebra
Chapter 3-Matrices Chapter 11 – Three Dimensional Geometry
Chapter 4-Determinants Chapter 12-Linear Programming
Chapter 5- Continuity and Differentiability Chapter 13-Probability
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Chapter 8-Application of Integrals

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