Statistics-Mean,Mode and Median - Future Study Point

Statistics-Mean,Mode and Median

mean,mode and median

MEAN,MODE AND MEDIAN NCERT 

Mean, mode and median are the terms of statistics which represent the central tendency of a data, The single value of the mean, mode or median tells us about the state of data. All of these three are important in solving statistical problems in economics, science, commerce, and other fields.

mean,mode and median

 

Mean- The mean of data represents the most common value of the data, it is calculated as follows.

When data is given as an individual series- Indidual series means when each value of the variable is given without showing its frequency.

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Example-

Find out the average weight of 5 people whose weights are given as follows.

45 kg, 50 kg, 40 kg,60 kg and 55 kg

 

So, the most common weight or average weight of 5 people in the given data is 50

Disadvantages of mean– The mean is unable to represent the data in the condition when data is skewed (much differences between larger values and the rest of the individual values of the data), then the median would be truer to represent the data, see the following example.

maths marks of 5 friends in a test560951065

 

Median- Median is called the middle term of the data provided data should be ascending order, the mean of the above data is 47 which is not representing the data properly so here median of the data will the best to show the nature of data of maths marks of 5 friends in a test.

maths marks of 5 friends in a test510606595

n = 5 (odd number)

m = 60

The median of this data is 60 is representing the given data in a better way because of the difference between the largest value and median is lesser than the difference between the largest value and mean.

When the individual data is given and the number of observations are even

Direct Method for evaluating the Mean

Discreet series- When frequencies are also given with the values of variable then such a series is known as discreet series, see the example

xFrequency
506
408
705
604
805

 

Mean of  such a data is given as follows

Solution-

xffx
506300
408320
705350
604240
805

∑f= 28

400

∑fx=1610

 

Determining the Median in case of discreet series-

xfcf
4088
50614
60418
70523
805

N=28

28

 

Therefore the median of the above data is 55.

The other ways of calculating mean are following

 Assumed mean method for evaluating the Mean

  Assuming an observation as a mean(A) and then forming the third column and then writing the deviation(d) each observation about the mean that is equal to the difference between observation and the assumed mean keeping in view the sign convention of the numbers, thereafter forming 4 th column and evaluating fd the product of deviation and their corresponding frequencies. After the table is formed then calculate the value of mean from the following formula.

∑fd is the addition of the product of deviation and corresponding frequencies and ∑f is the sum of total frequencies of individual observations.

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Step deviation method for evaluating Mean

 In this method, one more column is added d’ as compared to the assumed mean method, in this method deviation(d) is reduced by dividing the common factor(h )of all the deviations.

After evaluating d’ one more column of fd’ is also incorporated in the table and then calculate the mean from the following formula.

When the continuous series is given-

Class interval10-2020-3030-4040-5050-60
Frequency5102041

 

Solution-

Sr.n0Class intervalf(Frequency)x(Classmark)fx
110-2051575
220-301025250
330-402035700
440-50445180
550-6015555
∑f=40∑fx=1260

   

                                          

 

Other methods- (i) Assumed mean method- Already discussed above

 Step deviation method– Already discussed above

Median of the data when continuous series is given-

Class interval10-2020-3030-4040-5050-60
Frequency5102041

 

Solution- Median is calculated by using the following formula when continuous series is given

Class intervalFrequency(f)Cumulative frequency(cf)
10-2055
20-301015(cf)
30-4020(f)35
40-50439
50-60140(N)

The median group is N/2 th term of the series i.e N/2=40/2 = 20 th term which lies in 35 th term so the median group is 30-40

 

L = 30 (Lower limit of median class)

f =20 (Frequency of median class)

Hence the median of the given series is 32.5

The mode – In a series, the term with the highest frequency is known as mode of the series.

Mode of an individual series- When the individual measurements of the variable are given without showing their frequency then the terms with high frequency is known as a mode of the series.

 

Example- The performances of a student in 5 tests are given as follows, find the mode of data.

Testsiiiiiiivv
Percentage4o30504060

40 has the highest frequency so the mode of the above data is 40

Mode in a discreet series- When the frequency is also given of each term then such a series is known as discreet series.

Age of students in a class(in years)1315161412
Number of students764158

In the given data most numbers of students are of the age 14 so the mode of the data is 14.

Mode of the continuous series- Find the mode of the following series

The age of employs(in years)20-3030-4040-5050-6060-70
The number of employs305025152

 

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Solution –

The ages of employs(in years)frequency(f)
20-3030
30-4050
40-5025
50-6015
60-702

 

The mode(M ) of continuous series is calculated as follows

The class 30-40 has the highest frequency so it is mode group of above data

L = 40(lower limit of mode group)

f0= 30(preceding frequency of mode group)

f1= 50( frequency of mode group)

f2= 25 (successor   frequency of mode group)

i= Class interval of mode group


       

     

M = 30+ 4.44

M = 34.44

Hence the mode of the series is 34.44 

The relationship between Mean,Mode and Median

Mode = 3×Median – 2×Mean

NCERT Solutions of Science and Maths for Class 9,10,11 and 12

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