 Solutions of Most Important Science Questions For Class 10 CBSE Board Exam-Part 2 - Future Study Point # Solutions of Most Important Science Questions For Class 10 CBSE Board Exam-Part 2 # Solutions of Most Important Science Questions For Class 10 CBSE Board Exam-Part 2

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## Solutions of Most Important Science Questions For Class 10 CBSE Board Exam

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### Q1.Explain the function of fuse in a domestic electric circuit ? Anelectric oven having power rating 2000 W, 220V is used in an electriccircuit, having a fuse of 5A rating. What is likely to happen when theoven is switched on ? Explain.

Answer. The use of fuse is to protect the electrical appliances by the breaking of the circuit when the circuit is overloaded or excess current enters to the fuse.

In the given question we have

Power of oven(P) = V× I

I = 9.09 A

The fuse of 5A rating means it can allow the maximum current flow of 5A,any excess to this current (in this case 9.09A) melt it because H =I²RT,where H is heat,R is resistance and I is current so the circuit will be broken down and electrical appliances would be kept safe,but there may be chances of  short circuit  both of the wire of earth and fase stucked to each other because of excess heat , thus it results  the current flows in both the wire, this extra current results larger amount of heat so a fire could be taken place.

Q2. For the circuit diagram given below: Calculate :

(i) Value of current flowing through each resistor.

(ii) The total current in the circuit.

(iii) The total effective resistance of the circuit. Solutions.

(i) Since all the resistors are arranged in Parallel combination, therefore, the voltage across all resistors will be 6V

So applying ohm’s law V= IR

Let the current flowing through 5Ω, 10Ω and 30Ω are I, I2  and  Irespectively

(ii) Total electric current in the circuit ,I = I+ I2  + I=1.2 + 0.6 + 0.2  = 2 A

(iii) Let the total resistance is = R

1/R = 1/5 + 1/10 + 1/30

1/R = (6 + 3 +1)/30 = 10/30 = 1/3

R = 3 Ω

So total effective resistance of the circuit =3Ω

Q3. A resistance wire is stretched to double its length so that its
area of cross-section is halved. How will its resistance change ? Will

Answer.As we know the relationship among resistance(R), length of the conductor(l), area of cross-section of the conductor(A) and resistivity of the substance the conductor is made of(ρ) is following.

Let the resistance of the conductor becomes R’ after its length changes to 2l and area of the cross-section to A/2, so

Dividing eq.(i) by (ii)

R’ = 4R

Therefore the resistance of the conductor will become 4 times of the resistance as it was before.

The resistivity(ρ) of the substance is constant because substance remains the same in this change.

Q4. Give reasons for the following :

(i) Ionic compounds have high melting point and boiling point.

(ii) Ionic compounds conduct electricity in the molten state.

(iii) Ionic compounds are solids at room temperature and are somewhat hard.

Answer. Ionic compounds(like NaCl) are formed when one of the atom of the substance loss electrons forming cation(+ion) and atom of another substance gains the electrons forming anion(–ion), these anion and cation stucked to each other due to strong force of attraction between them ,obviously it will be needed high energy to overcome this strong electrostatic force between them,so their meling and boiling point is  high.

(ii) The flow of electricity occurs due to the movement of ions but in solid-state, there is no movement of ions in ionic compound. When ionic compounds are in the molten stage their ions become free to move,it is thats why in the molten stage ionic compound conducts electricity.

(iii) An ionic compound has a strong bond between their constituent cation and anion,it is required high temperature to separate them, the room temperature is very less (i.e almost 25°C) turning them into liquid. In this temperature, they are harder because of this strong force of attraction.

Q5. A compound which is prepared from gypsum has the property
of hardening when mixed with right quantity of water.

(i) Identify the compound and write its chemical formula.

(ii) Write the chemical equation for its preparation.

(iii) List any two uses of the above compound.

Answer.(i) The compound that prepared from the gypsum is Plaster of Peris(PoP),its chemical formula is  CaSO4.1/2.H2O.

(ii) When water is added to PoP in a proper quantity it turns into a hard substance called gypsum. PoP is produced by heating up gypsum.

(iii) (a) The property of Plaster of Paris turning to gypsum(hard substance) when water is added on it is used in manufacturing toys, statue, decorative items.

(b) Plaster of Paris is used widely in the hospitals in setting up fractured or broken bones in their place.

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 Chapter 1-Sets Chapter 9-Sequences and Series Chapter 2- Relations and functions Chapter 10- Straight Lines Chapter 3- Trigonometry Chapter 11-Conic Sections Chapter 4-Principle of mathematical induction Chapter 12-Introduction to three Dimensional Geometry Chapter 5-Complex numbers Chapter 13- Limits and Derivatives Chapter 6- Linear Inequalities Chapter 14-Mathematical Reasoning Chapter 7- Permutations and Combinations Chapter 15- Statistics Chapter 8- Binomial Theorem

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 Chapter 1-Relations and Functions Chapter 9-Differential Equations Chapter 2-Inverse Trigonometric Functions Chapter 10-Vector Algebra Chapter 3-Matrices Chapter 11 – Three Dimensional Geometry Chapter 4-Determinants Chapter 12-Linear Programming Chapter 5- Continuity and Differentiability Chapter 13-Probability Chapter 6- Application of Derivation CBSE Class 12- Question paper of maths 2021 with solutions Chapter 7- Integrals Chapter 8-Application of Integrals

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